Answer:

Step-by-step explanation:
We want to write an exponential function that goes through the points (0, 20) and (6, 1280). 
The standard exponential function is given by: 

The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence: 

Simplify: 

So, our exponential function is now: 

Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus: 

Solve for <em>b</em>. Divide both sides by 20: 

Therefore: 
![b=\sqrt[6]{64}=2](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B6%5D%7B64%7D%3D2)
Hence, our function is: 

 
        
             
        
        
        
Answer:
1. x=3,y=2
2.x=0,y=4
3.x=-3,y=6
4.x=6,y=0
Step-by-step explanation:
x=3, y=2
2(3)+3(2)=6+6=12
x=0, y=4
2(0)+3(4)=0+12=12
x=-3, y=6
2(-3)+3(6)=-6+18=12
x=6,y=0
2(6)+3(0)=12+0=12. Hope this helps!
 
        
             
        
        
        
Answer:


Step-by-step explanation:
Area:
 π
 π 
 π
 π  *Square 2x*
       *Square 2x*
 π
 π  *Divide by π*
          *Divide by π*
 *Divide by 4*
           *Divide by 4*
 *Square root*
             *Square root*
 *Solve*
           *Solve*
x ≈ 3.482
Now take the same equation but replace 2x with 3x
 π
 π 
Now replace x with 3.482 and solve for area.

Volume:
 π
 π  *Insert variables*
               *Insert variables*
 π
 π  *Cube 2x*
     *Cube 2x*
 π
 π  *Multiply
     *Multiply  on both sides*
 on both sides*
 π
 π  *Divide by π*
    *Divide by π*
 *Divide by 8*
           *Divide by 8*
 *Cube root*
             *Cube root*
![\sqrt[3]{10.770} = x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B10.770%7D%20%3D%20x) *Solve*
            *Solve*
x ≈ 2.208
Now take the same equation but replace 2x with 3x
 π
 π  
     
Now replace x with 2.208 and solve for volume.
