Answer:

Step-by-step explanation:
We want to write an exponential function that goes through the points (0, 20) and (6, 1280).
The standard exponential function is given by:

The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence:

Simplify:

So, our exponential function is now:

Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus:

Solve for <em>b</em>. Divide both sides by 20:

Therefore:
![b=\sqrt[6]{64}=2](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B6%5D%7B64%7D%3D2)
Hence, our function is:

Answer:
1. x=3,y=2
2.x=0,y=4
3.x=-3,y=6
4.x=6,y=0
Step-by-step explanation:
x=3, y=2
2(3)+3(2)=6+6=12
x=0, y=4
2(0)+3(4)=0+12=12
x=-3, y=6
2(-3)+3(6)=-6+18=12
x=6,y=0
2(6)+3(0)=12+0=12. Hope this helps!
Answer:


Step-by-step explanation:
Area:
π 
π
*Square 2x*
π
*Divide by π*
*Divide by 4*
*Square root*
*Solve*
x ≈ 3.482
Now take the same equation but replace 2x with 3x
π 
Now replace x with 3.482 and solve for area.

Volume:
π
*Insert variables*
π
*Cube 2x*
π
*Multiply
on both sides*
π
*Divide by π*
*Divide by 8*
*Cube root*
*Solve*
x ≈ 2.208
Now take the same equation but replace 2x with 3x
π
Now replace x with 2.208 and solve for volume.
