Take the right angled triangle with sides 13, 12 and 5. sine theta will be 12/13
When sin theta < 0 and cos theta < 0 we are in the third quadrant so sin theta will be -12/13
tan theta = sin theta / cos theta = -5/13 / -12/13 = -5*13 / -12*13 = 5/12
Y= -2X
Y= -2•3
Y= -6
X=3
Y= -2X
Y= -2•(-3)
Y=6
X= -3
Answer is y= -2X
Answer:
50
Step-by-step explanation:
ABCD is quadrilateral. Sum of all the angles in a quadrilateral is 360. This means angle ADC will be 130.
ADE is a straight line. Angle ADC and angle CDE should sum up to 180. From here we can infer that angle CDE=x is 50
Graph A is the correct one
