This is my work hope this helps.
Solution :
Let
and
represents the proportions of the seeds which germinate among the seeds planted in the soil containing
and
mushroom compost by weight respectively.
To test the null hypothesis
against the alternate hypothesis
.
Let
denotes the respective sample proportions and the
represents the sample size respectively.




The test statistic can be written as :

which under
follows the standard normal distribution.
We reject
at
level of significance, if the P-value
or if 
Now, the value of the test statistics = -1.368928
The critical value = 
P-value = 

= 0.171335
Since the p-value > 0.05 and
, so we fail to reject
at
level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the
of the seeds that
with the percent of the
in the soil.
a₁ = 4
n = 10
d = 3
a = a₁ + (n - 1)d
a₁₀ = 4 + (10 - 1)3
a₁₀ = 4 + (9)3
a₁₀ = 4 + 27
a₁₀ = 31
The 10th term would be 31 and the d variable will be replaced with the number 3.
Answer:
(0,0) r=5
Step-by-step explanation:
Answer: OPTION C.
Step-by-step explanation:
The systems of linear equations can have:
1. <u>No solution:</u> When the lines have the same slope but different y-intercept. This means that the lines are parallel and never intersect, therefore, the system of equations has no solution.
2. <u>One solution</u>: When the lines have different slopes and intersect at one point in the plane. The point of intersection will be the solution of the system
3. I<u>nfinitely many solutions</u>: When the lines have the same slope and the y-intercepts are equal. This means that the equations represents the same line and there are infinite number of solution.
Therefore, based on the explained above, the conclusion is: Systems of equations with different slopes and different y-intercepts <em><u>never</u></em> have more than one solution.