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stiv31 [10]
3 years ago
11

Which of the following Functions is NOT Linear? A:f(x)=x+0.5 B:F(x)=-x+0.5 C: F(x)=x^2-0.5 D: f(x)=0.5x

Mathematics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

<h2>C: f(x) = x² - 0.5</h2>

Step-by-step explanation:

The grsaph of the linear function is a straight line.

The equation of a line in the slope-intercept fomr is:

<em>y = mx + b</em>

where

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have:

A: f(x) = x + 0.5

it's a linear function: <em>m = 1, b = 0.5</em>

B: f(x) = -x + 0.5

it's a linear function: <em>m = -1, b = 0.5</em>

C: f(x) = x² - 0.5

it's not a linear function because in the equation is square of x (x²).

The graph of this function is a parabola.

D: f(x) = 0.5x

it's a linear function: <em>m = 0.5, b = 0</em>

Citrus2011 [14]3 years ago
6 0

Answer:

C: F(x)=x^2-0.5

Step-by-step explanation:

When the x is squared it's a parabola. A linear graph is shaped like a straight line, while a parabola is curved inward. I have included a graph of what that function would look like (tap/click on it to see the full graph.)

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The scale of a map is 1 in. = mi. Find each length on the map
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The question gives the relationship to be

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1 year ago
Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ
mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant.  But maybe you don't know it isn't and it's a "trick" to throw you off.  Hmm...

Anyways, the half angle identity for tangent is

tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.  

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5.  That makes the missing side, by Pythagorean's Theorem, -3.  Filling in our formula:

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) } which simplifies a bit to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }  and a bit more to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }

Bring up the lower fraction and flip it to divide to get

tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1} which of course simplifies to

-3.  Choice A.

6 0
3 years ago
Write an equation of a line that passes through (5,
enyata [817]

Answer:

y = 1/5x - 11

Step-by-step explanation:

perpendicular to a line means we flip the slope to opposite of what it is

in other wrds, since your slope is -5, your new slope for the line perpendicular to it would be 1/5.

Now we just use the same equation to find the y-intercept, which is b.

y = mx + b; m is your slope and b is your y intercept.

use the points given; (5, -10).

-10 = 1/5(5) + b

-10 = 1 + b

-11 = b

now put your equation together since you have all the pieces

y = 1/5x - 11

3 0
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Please help!<br><br> 2x-20°<br> x+5°<br> x=?
strojnjashka [21]

answer=

2 • (x - 10)

x + 5 is just x + 5

7 0
3 years ago
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