Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Step-by-step explanation:
Let x and y area the random variable that represents the heights of women and men.
Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.
i.e.
Since ,
Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).
[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]
Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.
i.e.
Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).
[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]
∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Answer:
<u>2</u><u>7</u><u> </u><u>+</u><u> </u><u>7</u><u>m</u>
Step-by-step explanation:
open the bracket:
I think it is: y=0.375x+3.125
a=(5-2)/(5- -3)=3/8=0.375
Find b
(5)=0.375(5)+b
(5)=1.875+b
5-1.875=b
b=3.125
Dance class is at 3:45pm, because the dance studio would not be open that early.