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Lunna [17]
3 years ago
11

True or false: Every sequence is either arithmetic or geometric. If this is true, explain. If false,

Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

In an arithmetic sequence, the difference between consecutive terms is constant. In formulas, there exists a number r such that

a_{n+1}-a_n=r\quad \forall n\geq 1

In an geometric sequence, the ratio between consecutive terms is constant. In formulas, there exists a number r such that

\dfrac{a_{n+1}}{a_n}=r\quad \forall n\geq 1

So, there exists infinite sequences that are not arithmetic nor geometric. Simply choose a sequence where neither the difference nor the ratio between consecutive terms is constant.

For example, any sequence starting with

1, 15, -3,\ldots

Won't be arithmetic nor geometric. It's not arithmetic (no matter how you continue it, indefinitely), because the difference between the first two numbers is 14, and between the second and the third is -18, and thus it's not constant. It's not geometric either, because the ratio between the first two numbers is 15, and between the second and the third is -1/5, and thus it's not constant.

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Find the common ratio of the geometric sequence.
Kay [80]

Answer:

The common ratio is \frac{1}{x^4}

Step-by-step explanation:

Geometric sequence:A geometric sequence is a sequence in which the ratio of any term to the preceding term of that term is always constant.

Common ratio: The ratio of any term to the  preceding term of that term.

The n^{th} term of a geometric sequence is represented by  a_n=ar^{n-1}.

The 1^{st} term of the sequence = a.

The sum of first n term is

S_n=\frac{a(1-r^n)}{1-r}

The common ratio = r.

Given geometric sequence,

\frac{1}{x^{10}} , \frac{1}{x^{14}}, \frac{1}{x^{18}},\frac{1}{x^{22}} ........

The common ratio is

=\frac{\textrm{second term}}{\textrm{first term}}

=\frac{\frac{1}{x^{14}}}{\frac{1}{x^{10}}}

=\frac{x^{10}}{x^{14}}

=\frac{1}{x^4}

6 0
4 years ago
The leaning tower of Pisa currently "leans" at a 4 degree angle and has a vertical height of 55.86 meters. How tall was the lean
Marizza181 [45]

Answer:

56 meters.

Step-by-step explanation:

Please find the attachment.

Let the leaning tower's be h meters tall, when it was originally built.

We can see from our attachment that the side with length 55.86 meters is hypotenuse and h is adjacent side for 4 degree angle.

Since we know that cosine relates the adjacent and hypotenuse of a right triangle.

\text{Cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}

Upon substituting our given values we will get,

\text{Cos (4)}=\frac{55.86}{h}

h=\frac{55.86}{\text{Cos (4)}}

h=\frac{55.86}{0.99756405026}

h=55.996\approx 56                      

Therefore, the leaning tower was approximately 56 meters, when it was originally built.

6 0
3 years ago
The number 110 is 60% of <br> what number?
kolezko [41]

Answer:

183.3333

Step-by-step explanation:

Let the number be X

Therefore

0.6X=110

X=110/0.6

X=183.3333

7 0
3 years ago
Help with This one please?
love history [14]
One. that is the definition of a line. 
Through any two points, there is exactly one line.
3 0
3 years ago
Determine whether the sequence converges or diverges. If it converges, give the limit.
azamat
The term to term rule is multiplying by 4 and if we continue doing this, we will move towards very large positive numbers.

This sequence, therefore, diverges to infinity
4 0
4 years ago
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