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2 years ago

I need help with this question

Mathematics

1 answer:

zavuch27 [327]2 years ago

4 0

Answer:

The letter is m and is usually to the left of x

Step-by-step explanation:

i think the equation is y=mx+b

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4. If A = 45° and B = 30°, verify the following (a) sin (A - B) = sinA.cosB - COSA, sinB.

noname [10]

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2 years ago

Factor the following polynomial: "4x2−16"

ra1l [238]

Answer:

Step-by-step explanation:

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2 years ago

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zzz [600]

Answer: 40%

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2 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

Step-by-step explanation:

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

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3 years ago

What is the product of 1 1/2 and -1 1/4?

Savatey [412]

positive number times negative number is negative number "(+)(-) = (-)".

$1\dfrac{1}{2}\cdot\left(-1\dfrac{1}{4}\right)=-\left(1\dfrac{1}{2}\cdot1\dfrac{1}{4}\right)$

we change the mixed numbers to the improper fractions

$=-\left(\dfrac{1\cdot2+1}{2}\cdot\dfrac{1\cdot4+1}{4}\right)=-\left(\dfrac{3}{2}\cdot\dfrac{5}{4}\right)=-\dfrac{3\cdot5}{2\cdot4}=-\dfrac{15}{8}=-1\dfrac{7}{8}$

6 0

3 years ago