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Alina [70]
4 years ago
10

If a coin rotates 160 degrees in 6 seconds,how many degrees does it rotate in 20 seconds?

Mathematics
1 answer:
nadya68 [22]4 years ago
6 0
Okay so this is how I would do it but you can do it a different way 
160/2 = 80 (2 b/c I want a whole # and 2 is a factor of 6 & 20) 
so 80 degree in 2 seconds 
so then 80 *10=800 (10 b/c 20/2=10)
but since there's only 360 degrees in a full circle 
800/360=2.22
so we go back to 80 *2.22=177.6 degrees 
-----------------------------------------------------------------------
v.s. 160           n
        ----     *    ---       (20 *160=3200/6=533.33
          6            20 

You can go w/ whatever answer you think is right b/c frankly I don't know but if I were you I would go with the second one because it seems more right and there's actually a method to the madness. 
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6m-2(7+3m)>5(2m-3)-m
Tpy6a [65]

Answer:

Therefore the value is

m

Step-by-step explanation:

Given:

6m-2(7+3m)>5(2m-3)-m ....Given

Step 1. Applying Distributive Property A(B+C)=AB+AC we get

6m-2\times7-2\times 3m>5\times 2m-5\times 3-m

6m-14-6m>10m-15-m\\-14>9m-15

Step 2. Add 15 both the side

-14+15>9m-15+15\\1>9m

Step 3. Dividing both the side by 9

\dfrac{1}{9}>\dfrac{9m}{9}\\\\\dfrac{1}{9}>m

Therefore the value is

m

4 0
4 years ago
What is the radius of a circle with circumference 17mm? Round to nearest tenth. Use 3.14
WINSTONCH [101]
     C = 2πr
   17 = 2(3.14)(r)
   17 = 2(3.14r)
   17 = 6.28r
 6.28   6.28
2.71 ≈ r
5 0
4 years ago
Which graph y > 1 -3x help please
VladimirAG [237]
The answer is the last graph, the equation says that y is greater than the equation making it a dashed line that is shaded above it
6 0
3 years ago
A bag contain 3 black balls and 2 white balls.
Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\

b)

Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}

c)

Probability of at least one black( means BB or BW or WB)

 =\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}

d)

Probability of at most one black ( means WW or WB or BW)

=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}

2)

a) Probability both black without replacement

  =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

b) Probability  of one black and one white

 =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

c) Probability of at least one black ( BB or BW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}

d) Probability of at most one black ( BW or WW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}

6 0
3 years ago
Solve for x:<br> x -20=3
elena55 [62]

Answer:

x = 23

Step-by-step explanation:

Add 20 to both sides of the equation

x-20=3

−20+20=3+20

Simplify

Solution:

x= 23

3 0
3 years ago
Read 2 more answers
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