Ask question

Ask question

All categories

3 years ago

12

Find the length of the curve yequalsthree fifths x superscript 5 divided by 3 baseline minus three fourths x superscript 1 divid

ed by 3 baseline plus 8 for 1less than or equalsxless than or equals27.

1 answer:

Kazeer [188]3 years ago

3 0

The answer is 333 so now it is equal

You might be interested in

Log*subscript*(3x − 2) 4096 = 3<br><br> I got x= negative 6 is this correct??

Brut [27]

Remember

$log_a(b)=c$ translates to $a^c=b$
and
$log_a(b^c)=clog_a(b)$
so

4096=16^3
$log_{3x-2}(4096)=3$
$log_{3x-2}(16^3)=3$
$3log_{3x-2}(16)=3$
divide both sides by 3
$log_{3x-2}(16)=1$
translate
$(3x-2)^1=16$
3x-2=16
add 2 to both sides
3x=18
divide both sides by 3
x=6

8 0

3 years ago

Help please! Ty!! ----

Tresset [83]

Answer:

5 4/9

Step-by-step explanation:

9 x 5 + 4= 5 4/9

BRAINLIEST PLZAESE

3 0

3 years ago

Please help I will mark brainliest I'm really in need now<br> (Please explain)

Ksivusya [100]

Answer:

i think the second question (the choose the Function) means choose the function that has changed the most.

the first choose function one, i dont know but... according to wikipedia, "an initial value problem is an ordinary differential equation together with an initial condition which specifies the value of the unknown function at a given point in the domain. Modeling a system in physics or other sciences frequently amounts to solving an initial value problem." hope this helps

Step-by-step explanation:

6 0

2 years ago

Solve for z<br> -p(d+z) = -2z+59−p(d+z)=−2z+59

alexira [117]

$-p(d+z)=-2z+59\qquad\text{use distributive property}\\\\-pd-pz=-2z+59\qquad\text{add pd to both sides}\\\\-pz=-2z+pd+59\qquad\text{add 2z to both sides}\\\\2z-pz=pd+59\\\\z(2-p)=pd+59\qquad\text{divide both sides by}\ (2-p)\neq0\\\\\boxed{z=\dfrac{pd+59}{2-p}}$

6 0

2 years ago

Enter three different expressions that are equivalent to, but not exactly the same as 1/4 + 5/4

choli [55]

Answer:

6/4 = 1 1/2

1 2/4

12/8

Step-by-step explanation:

7 0

2 years ago