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vaieri [72.5K]
3 years ago
12

Find the length of the curve yequalsthree fifths x superscript 5 divided by 3 baseline minus three fourths x superscript 1 divid

ed by 3 baseline plus 8 for 1less than or equalsxless than or equals27.
Mathematics
1 answer:
Kazeer [188]3 years ago
3 0
The answer is 333  so now it is equal
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Is the first number a multiple of the second? 56, 8:
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no

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no bc 8 is a multiple of 56, not 56 a multiple of 8

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What number is between 0-5
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In which quadrant do the points (-1,-2) and (-2,3) lie?​
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The number of kilograms of water in a human body varies directly as the mass of the body. An 87​-kg person contains 58 kg of wat
katen-ka-za [31]

Answer:

50 kg water.

Step-by-step explanation:

We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.

We know that two directly proportional quantities are in form y=kx, where y varies directly with x and k is constant of variation.

We are told that an 87​-kg person contains 58 kg of water. We can represent this information in an equation as:

58=k\cdot 87

Let us find the constant of variation as:

\frac{58}{87}=\frac{k\cdot 87}{87}

\frac{29*2}{29*3}=k

\frac{2}{3}=k

The equation y=\frac{2}{3}x represents the relation between water (y) in a human body with respect to mass of the body (x).

To find the amount of water in a 75-kg person, we will substitute x=75 in our given equation and solve for y.

y=\frac{2}{3}(75)

y=2(25)

y=50

Therefore, there are 50 kg of water in a 75​-kg person.

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3 years ago
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