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3 years ago

The constant of proportionality between the number of animals(a) at a zoo and the number of employees(e) that work there is 9/2.

Mathematics

1 answer:

belka [17]3 years ago

5 0

Step-by-step explanation:

i think the answer is 1/9

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Which expression is equivalent to ( 11 x − 8 ) + ( 7 − 4 x ) ?

dlinn [17]

Answer:

7x-1

Step-by-step explanation:

Use commutative property:

(11x-4x) + (-8+7) = 7x-1

6 0

2 years ago

Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec

vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

$\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}$

Hence, we have:

$\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\ \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}$

Divide the expression for the fifth term by the expression for the second term:

$\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}$

Substituting the value of r into any of the expression:

$\begin{gathered} ar\text{ = 18} \\ a\text{ }\times\text{ 2 = 18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}$

Hence, the explicit rule for the sequence is:

$a_n\text{ = 9\lparen2\rparen}^{n-1}$

5 0

1 year ago

In the coordinates of A are (-2,3) and the coordinates of B are (7,-1), find the length of AB

nekit [7.7K]

Answer:

√97

Step-by-step explanation:

5 0

2 years ago

Freee points bois firkmfmd

s2008m [1.1K]

you know

its rly hard to actually answer one of these

thx man i appreciate it

4 0

2 years ago

Read 2 more answers

Descried how to derive the quadratic formula from a quadratic equation in standard form

Aleks [24]

Answer:

The standard form of a quadratic equation is:

$ax^2+bx+c=0$ , $a\neq 0$

Quadratic Formula Derivation:

$ax^2+bx+c=0\\$

$x^2+\frac{b}{a}x+\frac{c}{a} =0$

$x^2+\frac{b}{a}x = -\frac{c}{a}$

Completing the Square:

$x^2+\frac{b}{a}x +\frac{b^2}{4a^2} = \frac{b^2}{4a^2}-\frac{c}{a}$

$( x+\frac{b}{2a} )^2 = \frac{b^2-4ac}{4a^2}$

Square Root property:

$x+\frac{b}{2a} = \pm \sqrt{ \frac{b^2-4ac}{4a^2}}$

$x = -\frac{b}{2a} \pm { \frac{\sqrt {b^2-4ac}}{2a}}$

$x = \frac{-b\pm\sqrt{b^2-4ac}} {2a} }$

8 0

2 years ago