1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121
Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
ANSWER :
1. 2ab + c^2
2. (a + b)^2 or (a^2 + 2ab + b^2)
3. 2ab
EXPLANATION :
Recall that the area of a triangle is 1/2 base x height.
and the area of a square is the square of its side.
From the problem, we have 4 congruent triangles.
The area of four triangles is :
The area of the square is :
Then the total area will be :
It is equivalent to the area of the whole square in which the side is (a + b)
So that's :
Since both expressions are equal, we can equate them :
y = x^2 + 1
y equals x squared plus 1
y = 4^2 + 1
y = 16 + 1
y = 17
