Answer:
There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.
Each car takes up 6m² and each bus takes up 30m².
However, there can only be 60 vehicles in the lot at any given time.
The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.
What is a possible car to bus ratio that would allow the lot to make profit?
Answer:
Link-local address
Explanation:
IP addresses that have "FE80" as the hexadecimal representation of their first 10 bits are IPV6 reserved addresses for link-local unicast addressing. These addresses are automatically configured (though may be manually configured too) on any interface and should not be routed. They are used for addressing on a single link with the main aim, among others, of automatic configuration and routing protocol advertisement. Devices attached to this link can be accessed or reached using the link-local addresses as they don't need a global address to communicate.
However, routers will not forward datagram or packets using link-local addresses. In other words, routers are not allowed to connect to the internet using the unicast link-local addresses.
Answer:
"A set is an unordered collection. A dictionary is an unordered collection of data that stores data in key-value pairs."
Explanation:
Set =>
Collection of non-repetitive elements.
Unordered
Unindexed
No way to change items.
Dictionary =>
Collection of key-value pairs.
Unordered
Indexed
Mutable
Answer:
Answered below
Explanation:
# Program is written in Python programming language
conditioner_in_ml = 0
width = float(input("Enter width in inches: "))
height = float(input("Enter height in inches: "))
length = float (input("Enter length in inches: "))
#Calculate the volume
volume = width * length * height
#Calculate the amount of conditioner per 100 #cubic inches of volume
conditioner_in_ml = volume/ 100
print("The amount of conditioner required for $volume cubic inches is $conditioner_in_ml ml")
Answer:
Altitude of the town(h1) = 1,196.8 m
Explanation:
Given:
Height of barometer(h) = 65 cm Hg = 0.65
Standard atmospheric pressure = 76 cm Hg = 0.76
Density of mercury(Pm) = 13,600 kg/m³
Density of air (Pa) = 1.25 kg/m³
Find:
Altitude of the town(h1)
Computation:
Pressure due column = Δp mercury column
(Pa)(h1) = (Pm)(h)
(1.25)(h1) = (13,600)(0.76-0.65)
(1.25)(h1) = 1,496
Altitude of the town(h1) = 1,196.8 m