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ahrayia [7]
2 years ago
9

A circle of having an area of 144 π sq.cm, is cut into two segments by a chord that is 6cm from the center of the circle.What is

the area of the smaller segment?
Mathematics
1 answer:
stepan [7]2 years ago
6 0

the area would be 43

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A piece of string 25 and 1/2 inches long will be cut into 3/4 inch pieces how many pieces will there be
olga2289 [7]

you would have 9.375 pieces or 75/8 pieces, depends on how you look at it

6 0
3 years ago
Put y-x=-8 of a line into slope-intercept form, simplifying all fractions.
grigory [225]

Answer: y= x-8

Step-by-step explanation:

  • Slope intercept form has a general formula of y=mx +b
  • m represents the slope of the line
  • b represents the value of the lines y-intercept

  • the equation must be rearranged into the general formula by isolating for 'y'

y-x=-8

  • to remove the x from the left side of the equation the opposite operation must be done to both sides

y-x+x=-8+x

  • the negative and positive x cancel out on the left side, leaving us with the equation with y by itself
  • now you can rearrange to put the equation into y=mx+b

Final Answer: y=x-8

4 0
1 year ago
A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hit the ground. a.Find
Lyrx [107]
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2 
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
4 0
3 years ago
2 1/6* 2 5/6 IN SIMPLEST FORM
andrezito [222]

Answer:

6 5/36

Step-by-step explanation:

MARK ME BRAINLIEST?

5 0
3 years ago
What is the answer to #3?
FrozenT [24]
I think it’s 2 but I’m not sure
5 0
2 years ago
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