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Alexxx [7]
3 years ago
7

Solve each system by graphing or using a table

Mathematics
1 answer:
tresset_1 [31]3 years ago
7 0
Attached is the graph and table

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Let f and g be functions. (a) The function (f + g)(x) is defined for all values of x that are in the domain(s) of ____________.
krok68 [10]

Answer:

a) for all values of x that are in the domains of f and g.

b) for all values of x that are in the domains of f and g.

c) for all values of x that are in the domains of f and g with g(x)≠0

Step-by-step explanation:

a) By definition (f+g)(x)=f(x)+g(x). Then x must be in the domain of f and g.

b) By definition (fg)(x)=f(x)g(x).  Then x must be in the domain of f and g.

c) By definition (f/g)(x)=f(x)/g(x).  Then x must be in the domain of f and g and g(x) must be different of 0.

5 0
2 years ago
Please help asap!
Alexeev081 [22]

Answer:

61.12

Hope this helps :3

3 0
2 years ago
Inqualities question pls help!
Margaret [11]

Answer:

B

Step-by-step explanation:

The closed circle at - \frac{3}{2} indicates that x can equal this value

The open circle at \frac{7}{2} indicates that x cannot equal this value.

All values of x between - \frac{3}{2} and \frac{7}{2} are valid, thus

- \frac{3}{2} ≤ x < \frac{7}{2} → B

5 0
2 years ago
Need help... help me
elena-s [515]
It’s 270 I believe good luck tho
5 0
2 years ago
The longer leg of a right triangle is 4 more than the short leg. The hypotenuse is eight less than the sum of the 2 legs.
Crazy boy [7]

Answer:

SteLet a = short leg of the right triangle, b = the longer leg, and c = the hypotenuse.

The longer leg of a right triangle is 4inches longer than the shorter leg: b = a + 4

The hypotenuse is 8inches longer than the shorter leg:  c = a + 8

 

Use the Pythagorean Theorem:

 

a2 + b2 = c2

a2 + (a+4)2 = (a+8)2

a2 + a2 + 8a + 16 = a2 + 16a + 64

a2 - 8a - 48 = 0

 

Factors to:

 

(a-12)(a+4) = 0

a = 12, -4

 

Since we can't have a side of -4, a = 12

Shorter Leg = 12 inches

Longer Leg = 12 + 4 = 16 inches

Hypotenuse = 12 + 8 = 20 inches

6 0
3 years ago
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