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3 years ago

14

Explain how to use absolute value to find the distance between (-2,-2) and (-2,5)

1 answer:

dem82 [27]3 years ago

6 0

The absolute value of a number is its distance away from zero. Depending on how far away a number is, it has a less or greater absolute value. (-2,-2) have the same absolute value while (-2,5) have a different absolute value. Which has a greater absolute value? -25 or 6? The answer: -25, it is farther away from zero.

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Take 2y 2 - 3y - 5 from y 3 - 6y 2 + 5y. Select the correct answer.

NNADVOKAT [17]

Answer:

$y^3-8y^2+8y+5$

Step-by-step explanation:

Take one polynomial from the other means to perform the sub.traction of them. Recall that it is better to use grouping symbols when subtracting polynomials, so we get the signs right when combining like terms:

The indicated subtraction is: $y^3-6y^2+5y - (2y^2-3y-5)$

Make sure that before removing the grouping symbol (parenthesis) that is preceded by a negative sign, we change the signs of every term inside it. Then combine like terms to get the final answer:

$y^3-6y^2+5y - (2y^2-3y-5)=\\=y^3-6y^2+5y-2y^2+3y+5=\\=y^3-6y^2-2y^2+5y+3y+5=\\=y^3-8y^2+8y+5$

Which is the last option shown in the question

3 0

3 years ago

Find the distance, c, between (–3, –4) and (1, 5) on the coordinate plane. Round to the nearest tenth if necessary.

nexus9112 [7]

Answer:

I believe the answer 16

Step-by-step explanation:

All you have to do is count.

8 0

2 years ago

A lizard is at the bottom of a 19-foot well. Each day it crawls up 5 feet, but each night it slips back 4 feet. After how many

amm1812

It travels a foot each day so it would take 20 days to fall back down to 19

7 0

3 years ago

An object is launched straight into the air. The projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t

ratelena [41]

Answer with Step-by-step explanation:

We are given that height of projectile after t seconds is given by

$h(t)=96t-16t^2$

a.h(t)=144 ft

$144=96t-16t^2$

$16t^2-96t+144=0$

$t^2-6t+9=0$

$t^2-3t-3t+9=0$

$t(t-3)-3(t-3)=0$

$(t-3)(t-3)=0$

t-3=0

t=3

After 3 s, the height of the project will be 144 feet in the air.

b.h(t)=0

$96t-16t^2=0$

$16t(6-t)=0$

$16t=0\implies t=0$

$6-t=0\implies t=6$

At t=0, the initial position of projectile

At t=6 s , the projectile will hit the ground.

6 0

3 years ago

Solve for z.<br><br> ln63=lnz+ln7<br><br> Enter your answer in the box.

Bumek [7]

Answer:

<em>z </em>= 9

Step-by-step explanation:

ln 63 = ln z + ln 7

We have the formula:

ln A + ln B = ln AB

So, ln 63 = ln 7<em>z</em>

7<em>z </em>= 63

Divide both sides by 7.

$\frac{7z}{7}=\frac{63}{7}$

<em>z</em> = 9

7 0

3 years ago

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