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marysya [2.9K]
2 years ago
14

How do u multiply x^2-4 over x^2-1 times x+1 over x^2+2x

Mathematics
2 answers:
Anna11 [10]2 years ago
6 0
\frac{x ^ 2-4 }{x ^ 2-1}*\frac{ x + 1 }{x ^ 2 +2 x}=\frac{x ^ 2-2^2 }{x ^ 2-1}*\frac{ x + 1 }{x(x +2 )} =\\ \\ \\ =\frac{(x -2)\not(x+2)^1 }{(x -1)\not(x+1)^1}*\frac{ \not(x + 1)^1 }{x\not(x +2)^1 }= \frac{ x-2 }{x(x-1)} \\ \\ \\ \\a^2-b^2 =(a-b)(a+b)


mixer [17]2 years ago
5 0
(X2-4)/(x2-1).  *  (x+1)/(x2+2x)
[(x-2)(x+2)]/[(x-1)(x+1)]. * (x+1)[x(x+2)]
(x-2)/(x-1) * 1/x
(x-2)/(x2-x)
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Answer: About 3.06

Step-by-step explanation:

  We can use trigonometry functions to solve for AC. Let the ?, representing AC, be "x" in our mathematical work.

  Since we have the hypotenuse and x is adjacent to the angle given, I am going to use cosine.

      cos(θ) = \frac{adjacent}{hypotenuse }

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ExtremeBDS [4]

The value of the F(1) is 1/2 option (C) is correct after plugging the value of t = 1 in the provided function.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is attached in the picture please refer to the picture.

We have a function:

\rm F(t) = 4\dfrac{1}{2^{3t}}

Plug t = 1

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After solving:

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Thus, the value of the F(1) is 1/2 option (C) is correct after plugging the value of t = 1 in the provided function.

Learn more about the function here:

brainly.com/question/5245372

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