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marysya [2.9K]
3 years ago
14

How do u multiply x^2-4 over x^2-1 times x+1 over x^2+2x

Mathematics
2 answers:
Anna11 [10]3 years ago
6 0
\frac{x ^ 2-4 }{x ^ 2-1}*\frac{ x + 1 }{x ^ 2 +2 x}=\frac{x ^ 2-2^2 }{x ^ 2-1}*\frac{ x + 1 }{x(x +2 )} =\\ \\ \\ =\frac{(x -2)\not(x+2)^1 }{(x -1)\not(x+1)^1}*\frac{ \not(x + 1)^1 }{x\not(x +2)^1 }= \frac{ x-2 }{x(x-1)} \\ \\ \\ \\a^2-b^2 =(a-b)(a+b)


mixer [17]3 years ago
5 0
(X2-4)/(x2-1).  *  (x+1)/(x2+2x)
[(x-2)(x+2)]/[(x-1)(x+1)]. * (x+1)[x(x+2)]
(x-2)/(x-1) * 1/x
(x-2)/(x2-x)
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Step-by-step explanation:

Given

(x^\frac{3}{8})^\frac{3}{4}

Required

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(x^\frac{3}{8})^\frac{3}{4}

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(x^\frac{3}{8})^\frac{3}{4} = x^\frac{9}{32}

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