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inysia [295]
4 years ago
10

Y=2x-10 substitution Y=4x

Mathematics
1 answer:
Arada [10]4 years ago
4 0
X=5
 Work:

y=2x-10
4x=2x-10
2x=10, then divide 2x on each side
x=5
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The probability of sandy flipping a coin twice and getting heads both times is 0.25 the probability of john's spinner stopping o
Rom4ik [11]

The true statement is (c) Neither. Both events are equally likely.

<h3>Complete question</h3>

The probability of Sandy flipping a coin twice and getting heads both times is 0.25. The probability of John's spinner stopping on the color red is 1/4.

Which of these events is more likely?

-Sandy flips a coin twice and gets heads both times.

-John's spinner stops on the color red.

-Neither. Both events are equally likely.

<h3>How to determine the likely event?</h3>

The given parameters are:

P(Head twice) = 0.25

P(Red) = 1/4

Rewrite P(Red) as:

P(Red) = 0.25

By comparison, we have:

P(Red) = P(Head twice) = 0.25

This means that both events are equally likely

Hence, the true statement is (c)

Read more about probability at:

brainly.com/question/966102

#SPJ1

8 0
2 years ago
Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:
kondaur [170]
\text{Proof by induction:}
\text{Test that the statement holds or n = 1}

LHS = (3 - 2)^{2} = 1
RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS
\text{Thus, the statement holds for the base case.}

\text{Assume the statement holds for some arbitrary term, n= k}
1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}

\text{Prove it is true for n = k + 1}
RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}

LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}
= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}
= \frac{k(6k^{2} + 15k + 11) + 2}{}
= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}
= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}
= RHS

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.
3 0
4 years ago
Which is the function represented by the table?
Paha777 [63]
The function represented by the table is linear function
and pass with (0,0)
so it is in the form
             f(x) = m x
where m is the slope

m = [ f(x₂) - f (x₁) ] / [ x₂ -x₁]
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so
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4 0
3 years ago
Find the distance between​
Dmitry_Shevchenko [17]

Answer:

minus 15 by 4

Step-by-step explanation:

minus 9 by 4 minus 3 by 2 lcm then add

6 0
3 years ago
Graph the function y = -2x + 1 using inputs of -1,0, 1, and 2.
Vladimir [108]

Answer:   (-1,3)

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               (1,-1)

              (2,-3)

Step-by-step explanation: For example, you put -1 as x in the equation, and then solve, your answer would be the y, and the number you inputted would be the x.

3 0
4 years ago
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