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Harman [31]
3 years ago
6

$49.95 pair of shoes; 5% tax

Mathematics
2 answers:
Keith_Richards [23]3 years ago
6 0

Answer:

$52.44

Step-by-step explanation:

Anton [14]3 years ago
6 0

Answer:

$2.4975 rounded up is $2.50

Step-by-step explanation:

5/100 of 49.95

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Evaluate (2 - 5i)(p + q)i when p = 2 and q = 5i<br>a. 29i<br>b. 291-20<br>C.-21i<br>d.29​
attashe74 [19]

Answer:

A. 29i

Step-by-step explanation:

Step 1: Plug in given variables

(2 - 5i)(2 + 5i)i

Step 2: Difference of squares (expand)

(4 - 25i²)i

Step 3: Imaginary numbers rules

(4 - 25(-1))i

Step 4: Combine like terms

(4 + 25)i

(29)i

Your final answer will be 29i

8 0
3 years ago
Read 2 more answers
I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu
ra1l [238]

The imaginary unit i belongs to the set of complex numbers, denoted by \mathbb C. These numbers take the form a+bi, where a,b are any real numbers.

The set of real numbers, \mathbb R, is a subset of \mathbb C, where each number in \mathbb R can be obtained by taking b=0 and letting a be any real number.

But any number in \mathbb C with non-zero imaginary part is not a real number. This includes i.

  • "is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because 2=2+0i.

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising i to the i-th power. Since i=e^{i\pi/2}, we have

i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079

3 0
3 years ago
When you substitute a value for x or y, you are x or y with a value.
Hitman42 [59]

Step-by-step explanation:

See whenever we have two variables like x and y.

And also we have given two equations in terms of x and y.

Example: ax + by = p  and cx + dy = q

In order to get the solution, we need to find the value of x and y using the given two equations.

So here what we can do is:

Consider any one equation and get x or y from that equation.

i.e consider ax + by = p  or x = \frac{1}{a}*(p-by)

Now plug value of x (or y) from the equation you have considered into the another equation.

i.e c(\frac{1}{a}*(p-by))+dy = q

Now solve this equation to get y (or x).

and after that we can find the other variable.


4 0
3 years ago
Read 2 more answers
Jenny is taking a vacation from Florida. She travels 70 kilometers per hour for 2 hours, and 63 kilometers per hour for 5 hours.
crimeas [40]

Answer: 65 kmh

Step-by-step explanation:

70 kmh for 2 hours = 140 km.

63 kmh for 5 hours = 315 km

140 + 315 = 455/7 total hours = 65 kmh

3 0
3 years ago
Ignoring leap days, the days of the year can be numbered 1 to 365. Assume that birthdays are equally likely to fall on any day o
faust18 [17]

Answer:

Follows are the solution to the given question:

Step-by-step explanation:

They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.

S=365^n

This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.

P(x)=\frac{1}{365^{n}}

if x is between 1 and 365 as well as the occurrence is just all similarly possible

In point i:

That somebody mentions their birthday throughout the party

Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.

In point ii:

Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.

In point iii:

Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.

6 0
3 years ago
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