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Mrrafil [7]
3 years ago
6

An expression is shown. (2.8 + 9.46) × 4.5 What is the value of the expression?

Mathematics
2 answers:
kozerog [31]3 years ago
5 0

Answer:

55.17

Step-by-step explanation:

2.8 + 9.46 = 12.26

12.26 x 4.5 = 55.17

Naddika [18.5K]3 years ago
3 0

Answer:

55.17

Step-by-step explanation:

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What is the answer to the question down below
ratelena [41]

We conclude that the measure of that angle is 150 degrees.

<h3>How to get the measure of angle BFE?</h3>

Notice that  the measure of angle ∠BFE will be equal to:

∠BFE = ∠BFC + ∠CFD + ∠DFE

Where:

∠CFD = 90°

∠DFE = 30°

And we will have that:

∠AFC = 180° - 90° - 30° = 60°

And we know that BF bisects that angle, then:

∠BFC = 30°

So we conclude that:

∠BFE = ∠BFC + ∠CFD + ∠DFE = 30° + 90° + 30° = 150°

We conclude that the measure of that angle is 150 degrees.

If you want to learn more about angles:

brainly.com/question/17972372

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5 0
2 years ago
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solmaris [256]

Answer:

The probability of a person going to work by car is 48

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As it's represented in the table above, there are 48 percent employees use cars as their transportation to work, and to find the rest sum all the probability of other transportation together which will give you 52 percent.

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2 years ago
Out of the 40 students in the 7th grade 60% of the students carry cell phones. What fraction of the students carry a cell phone?
nexus9112 [7]
If you have 60% out of 40 students that is 24 students
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3 years ago
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Determine whether each of the following pairs of angles have equal measures. Drag and drop each pair
never [62]

Answer:

MJK & PJR = Unequal

LJP & NJR = Equal

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MJP & PJR = Unequal

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4 years ago
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Answer:

{ \sf{( \sec \theta -  \csc \theta)(1 +  \tan \theta +  \cot \theta) }} \\  = { \sf{( \sec \theta +  \tan \theta \sec \theta +  \cot  \theta \sec  \theta) - ( \csc  \theta -   \csc \theta \tan  \theta -  \csc \theta \cot  \theta)}} \\  = { \sf{( \sec \theta +  \sec \theta \tan  \theta +  \csc  \theta) - (  \csc  \theta -  \sec \theta -  \csc  \theta \cot   \theta)}} \\  = { \sf{ \sec  \theta \tan  \theta +  \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}

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3 years ago
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