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inna [77]
4 years ago
8

Apakah yang melibatkan perubahan kimia

Physics
1 answer:
UkoKoshka [18]4 years ago
7 0
Melakukan apa yang melibatkan perubahan kimia
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A constant torque is applied to a rigid wheel whose moment of inertia is 2.0 kg · m2 around the axis of rotation. If the wheel s
Jlenok [28]

Answer:

The applied torque is 3.84 N-m.      

Explanation:

Given that,

Moment of inertia of the wheel is 2\ kg-m^2

Initial speed of the wheel is 0 (at rest)

Final angular speed is 25 rad/s

Time, t = 13 s

The relation between moment of inertia and torque is given by :

\tau=I\alpha \\\\\tau=I\times \dfrac{\omega_f}{t}\\\\\tau=2\times \dfrac{25}{13}\\\\\tau=+3.84\ N-m

So, the applied torque is 3.84 N-m.

4 0
3 years ago
One wire carries a current of I1= 2 Amps, and the other carries a parallel current (same direction, wires are side by side) of I
Yuki888 [10]

Answer:F=3\times 10^{-5} N

Explanation:

Given

I_1=2 Amps

I_2=0.75 Amps

Length of each wires\left ( L\right )=5 m

Distance between wires \left ( r\right )=5 cm

Force per unit length =\frac{\mu_0I_1I_2}{2\pi r}

F'=\frac{2\times 10^{-7}\times 2\times 0.75}{2\pi \times 0.05}

F'=6\times 10^{-6}

Force for L=5 m

F=3\times 10^{-5} N

6 0
3 years ago
The question is “Which direction will the airplane move” plz help :,)
masha68 [24]
The answer would be that the plane would move upward and to the right! Hope this helps, message me if you need more help!
~PLUTO100
7 0
4 years ago
Read 2 more answers
How might variation in the color of beetles help them survive ?
GREYUIT [131]

Answer:

they can blend in with their suroundings

Explanation:

3 0
3 years ago
Pun zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que caminar hay un insta
Mars2501 [29]

Answer:

Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.

Explanation:

Según la Física, comprendemos que la presión es igual a la fuerza dividida por área. En este caso, el peso de la persona dividida por área total de los tacos de los zapatos de golf suponiendo una distribución uniforme de la fuerza. Es decir:

\sigma = \frac{W}{n\cdot A_{T}} (Eq. 1)

Donde:

\sigma - Presión, medida en libras por pulgada cuadrada.

W - Peso de la persona, medida en libras.

n - Cantidad de tacos en los zapatos, adimensional.

A_{T} - Área del taco, medida en pulgadas cuadradas.

Si conocemos que W = 180\,lb, n = 20 y A_{T} = 0.01\,in^{2}, la presión es:

\sigma = \frac{180\,lb}{(20)\cdot (0.01\,in^{2})}

\sigma = 900\,psi

Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.

3 0
3 years ago
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