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Debora [2.8K]
3 years ago
7

What is the number of electrons that can be held in the first orbit closest to the nucleus

Chemistry
1 answer:
Juliette [100K]3 years ago
5 0
The first shell can hold up to 2 electrons, the second shell can hold up to 8 (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on.
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I typed a question. It said give points. I selected. Someone answered notification came. But where do I see they persons answer?
Ksivusya [100]

Answer:

212.304 grams

Explanation:

similar to your other question, use the same formula

q=mCpΔT

23617=m(4.182)(46.6-20)

23617=111.2412m

m=212.304g

6 0
2 years ago
Explain how lone pairs of electrons influence the shape of a molecule.
Ronch [10]

Explanation:

the lone pairs will be negatively charged. these have a repulsion effect on other negatively charged electrons in the shells of atoms. picture a water molecule: the lone electron pair on the top of the oxygen will have a repulsion force on the 2 hydrogen atom's orbiting electrons to cause a bent molecular geometry.

3 0
3 years ago
Which is smaller 25 mm or 25cm
umka21 [38]

Answer:

25 mm is smaller.

5 0
3 years ago
Thermochemistry
max2010maxim [7]
THe Answer is 105 J

hope this helps and please brainliest, I was first :)
4 0
3 years ago
A bike rider approaches a hill with a speed of 8.5 m/s. The total mass of the bike and the rider is 85 kg. Find the kinetic ener
krek1111 [17]

KE=3070.625 J

Height = 3.686 m

<h3>Further explanation</h3>

mass of bike+rider=85 kg

velocity = 8.5 m/s

\tt KE=\dfrac{1}{2}mv^2\\\\KE=\dfrac{1}{2}\times 85\times 8.5^2\\\\KE=3070.625~J

Conservation of energy :

(KE+PE)₁ (downhill) = (KE+PE)₂ (up the hill)

PE₁=0⇒h=0

KE₂=0⇒v=0(stop), so equation becomes :

KE₁=PE₂

\tt KE_1=3070.625\\\\KE_1=mgh_2\\\\3070.625=85\times 9.8\times h\Rightarrow h=3.686~m

5 0
3 years ago
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