Answer:
<u><em>See attachment for explanations.</em></u>
Explanation:
Answer: There are
atoms present in 0.500 mol of
.
Explanation:
According to the mole concept, there are
atoms present in 1 mole of a substance.
In a molecule of
there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of
are as follows.

Thus, we can conclude that there are
atoms present in 0.500 mol of
.
The mass fraction of sodium chloride is 0.0625
<h3>What is the mass fraction of sodium chloride in the solution?</h3>
The mass fraction of sodium chloride is the ratio of the mass of sodium chloride to the total mass of the solution.
The mass fraction of sodium chloride is determined as follows;
mass of sodium chloride = 20 g
- mass of water = volume * density
density of water = 1 g/mL
volume of water = 300 mL
mass of water = 300 mL * 1 g/mL
mass of water = 300 g
total mass of solution = 20 + 300 = 320 g
mass fraction of sodium chloride = 20/320
mass fraction of sodium chloride = 0.0625
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Answer: Fluorine and chlorine are gases. Bromine is one of only two liquid elements, and iodine is a solid.
Answer:
E = 0.062 V
Explanation:
(a) See the attached file for the answer
(b)
Calculating the voltage (E) using the formula;
E = - (2.303RT/nf)log Cathode/Anode
Where,
R = 8.314 J/K/mol
T = 35°C = 308 K
F- Faraday's constant = 96500 C/mol,
n = number of moles of electron = 2
Substituting, we have
E = -(2.303 * 8.314 *308/2*96500) *log (0.03/3)
= -0.031 * -2
= 0.062V
Therefore, the voltmeter will show a voltage of 0.062 V