All you need to do is to look at both sides of the equation and see who has the same element, state, coefficient, and charge and those will be your spectator ions.
In this question, the spectator ions would be 
and 
.
The reaction between oxygen, O2, and hydrogen, H2, to produce water can be expressed as,
2H2 + O2 --> 2H2O
The masses of each of the reactants are calculated below.
2H2 = 4(1.01 g) = 4.04 g
O2 = 2(16 g) = 32 g
Given 1.22 grams of oxygen, we determine the mass of hydrogen needed.
(1.22 g O2)(4.04 g H2 / 32 g O2) = 0.154 g of O2
Since there are 1.05 grams of O2 then, the limiting reactant is 1.22 grams of oxygen.
<em>Answer: 1.22 g of oxygen</em>
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The major residences to be able to be mentioned in this text are its appeal to polar molecules, its high specific warmth, the excessive warmness of vaporization, the decrease density of ice, and its high polarity.
The primary homes of water are its polarity, concord, adhesion, floor anxiety, excessive unique warmth, and evaporative cooling. A water molecule is barely charged on each ends. this is because oxygen is more electronegative than hydrogen.
Water is good sized functionality to dissolve a ramification of molecules has earned it the designation of “standard solvent,” and it's far this capacity that makes water such an invaluable life-sustaining pressure. On a biological level, water's role as a solvent facilitates cells transport and use substances like oxygen or vitamins.
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I’m not exactly sure but my guess is (B)
First, we have to get Kb from this formula:
Pkb = - ㏒ Kb
by substitution by Pkb value = 5.79
5.79 = -㏒ Kb
∴Kb = 1.62x10^-6
From the ICE table
morphine ↔ C+ + OH-
initial 0.105 0 0
change -X +X +X
Equilibrium (0.105-X) X X
So Kb = [C+] [OH-]/[morphine]
by substitution
1.62x10^-6 = X^2 / (0.105-X)
X^2+ 1.6x 10^-6 X - 1.68x10^-7 / (X- 0.105) = zero by solving the equation for X
∴X =4 x 10 ^-4 or 0.0004
∴[OH-] = 0.0004
by substitution we can get POH
when POH = -㏒[OH-]
= -㏒0.0004
= 3.398
and when PH + POH = 14
∴PH = 14 - 3.398 = 10.6
