Answer:
The Length of swimming pool is 8.35 feet
The width of swimming pool is 5.35 feet
Step-by-step explanation:
Given as :
The length of swimming pool is 3 feet longer that its width
Let The width of swimming pool = w feet
So, The Length of swimming pool = L = (w + 3) feet
Now, The swimming pool is surrounded by deck of 2 feet wide
The width of deck = w' = w + 2 + 2 = (w + 4) feet
The area of deck = 116 feet²
The length of deck = L' = L + 2 + 2 = (L + 4) feet
So, L' = (w + 3 + 4) feet
I.e L' = (w + 7) feet
∵ The area of deck = 116 feet²
So , L' × w' = 116 feet²
(w + 7)× (w + 4) = 116
Or, w² + 4 w + 7 w + 28 = 116
Or, w² + 11 w - 88 = 0
Solving the quadratic equation as
ax² + bx + c = 0
So, w = ![\dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}](https://tex.z-dn.net/?f=%5Cdfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E%7B2%7D-4%5Ctimes%20a%5Ctimes%20c%7D%7D%7B2%5Ctimes%20a%7D)
Or, w = ![\dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}](https://tex.z-dn.net/?f=%5Cdfrac%7B-11%5Cpm%20%5Csqrt%7B11%5E%7B2%7D-4%5Ctimes%201%5Ctimes%20%28-88%29%7D%7D%7B2%5Ctimes%201%7D)
Or, w = ![\dfrac{-11\pm \sqrt{473}}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B-11%5Cpm%20%5Csqrt%7B473%7D%7D%7B2%7D)
or, w = ![\dfrac{-11\pm 21.7}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B-11%5Cpm%2021.7%7D%7B2%7D)
or, w = 5.35 , -16.35
The width of swimming pool = w = 5.35 feet
The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet
Hence, The Length of swimming pool is 8.35 feet
And The width of swimming pool is 5.35 feet
Answer