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PilotLPTM [1.2K]
3 years ago
14

2/5 of the instruments in the marching band are brass one third or percussion and the rest are wood ones 1/8 of the brass instru

ments or two bus if there are 240 instruments in the band how many are tubers
Mathematics
1 answer:
kvasek [131]3 years ago
5 0
There are twelve tubas in the band. And btw you should work on your spelling. I tutor. So if you want my help just message me.
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Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%
Nataly [62]

Step-by-step explanation:

<h3>\sec \alpha  \sqrt{1 -  \sin ^{2}   \alpha }  = 1</h3>

Prove the LHS

Using trigonometric identities

That's

<h3>\cos ^{2}  \alpha  = 1 -  \sin^{2}  \alpha</h3>

<u>Rewrite the expression</u>

We have

<h3>\sec \alpha  \sqrt{ \cos^{2} \alpha  }</h3>

<h3>\sqrt{ { \cos }^{2}  \alpha }  =  \cos \alpha</h3>

So we have

<h3>\sec  \alpha  \times  \cos \alpha</h3>

Using trigonometric identities

<h3>\sec \alpha  =  \frac{1}{ \cos \alpha }</h3>

<u>Rewrite the expression</u>

That's

<h3>\frac{1}{\cos \alpha }  \times  \cos \alpha</h3>

Reduce the expression with cos a

We have the final answer as

<h2>1</h2>

As proven

Hope this helps you

7 0
3 years ago
find the slope intercept form of the equation of the the line that passes through (-9,-8) and the origin
Debora [2.8K]

Answer:

The answer is y=8/9x

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
What is the solution set for this inequality?
olasank [31]

Step-by-step explanation:

  • -9x+18<-27
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6 0
3 years ago
Hello chaps, please help me with this absurb eqution, "I think of a number add one then double the result
ziro4ka [17]

Answer:

2n+2

Step-by-step explanation:

Let the number = n.

Add 1 to n:

n+1

Double n+1:

2(n+1)

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2n+2

6 0
3 years ago
What is 2=(n+q3)h please answer asap its for edgenuity.
meriva

Answer:

Hi there!

Your answer is:

n= 2/h - q^3

q= \sqrt[3]{\frac{2}{h}-n }

h= 2 / (n+q^3)

Step-by-step explanation:

2=(n+q^3)h

/h

2/h = (n+ q^3)

-q^3

2/h-q^3 = n

2=(n+q^3)h

/h

2/h = n+q^3

-n

2/h - n= q^3

\sqrt[3]{\frac{2}{h}-n } = q

2= (n+q^3)h

/n+q^3

2 / (n+q^3) = h

Hope this helps and that edge is going well :D

Signed,

A fellow Edge Student ;)

5 0
4 years ago
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