To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
You are given two equations, solve for one variable in one of the equations. Say you solved for x in the second equation. Then, plug in that value of x in the x of the first equation. Solve this (first) equation for y (as it should become apparent) and you'll get a number value. Plug in this numerical value of y into the y of the second equation. Solve for x in the second equation. And there you have it: (x, y)
Answer:
M' is {-5, -4, -3, -2, -1, 0, 1, 3, 5, 6}
Step-by-step explanation:
Answer:
The required proof is shown below.
Step-by-step explanation:
Consider the provided figure.
It is given that KM=LN
We need to prove KL=MN
Now consider the provided statement.
KM = LN Given
KM = KL+LM Segment addition postulate
LN = LM+MN Segment addition postulate
KL+LM = LM+MN Substitution property of equality
KL = MN Subtraction property of equality
The required proof is shown above.
<h2>
Hello!</h2>
The answer is: 23.77 hours
<h2>
Why?</h2>
Where:
Total(t) is equal to the amount for a determined time (in hours)
<em>Start</em> is the original amount
<em>t </em>is the time in hours.
For example, it's known from the statement that the bacteria double their population every 15 hours, so it can be written like this:
To calculate how long it takes for the bacteria cells to increase to 300, we should do the following calculation:
So, to know if we are right, let's replace 23.77 h in the equation:
Total(t)=100*2^\frac{23.77}{15}=299.94
and 299.94≅300
Have a nice day!
