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pychu [463]
3 years ago
12

A solution is made by adding 50 grams of gelatin to 400 grams of water. What is the mass % of water in the sample?

Chemistry
1 answer:
Marina86 [1]3 years ago
5 0
Adding 50 grams of gelatin and 400 grams of water will give us a mixture with a total mass of 450 grams. The percent mass of water is calculated by dividing the mass of water by the total mass and multiply by 100.
                      mass % = (400 / 450) x 100% = 88.89%
Thus, there is approximately 88.90% of water in the sample. 
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What is the mass of potassium chloride when 6.75 g of potassium reacts with an excess of chlorine gas? the balanced chemical equ
lorasvet [3.4K]
The balanced equation for the above reaction is;
2K + Cl₂ ---> 2KCl
Stoichiomtery of K to KCl is 2:2
Potassium is the limiting reactant which is fully consumed in the reaction. The amount of product formed depends on amount of limits reactant present.
Number of moles of K reacted - 6.75 g/ 39 g/mol = 0.17 mol
Therefore number of KCl moles formed - 0.17 mol
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6 0
3 years ago
Please help asap 18 points if help and right answer please ​
barxatty [35]

Answer:

Lithium = 8%

Bromine = 92%

Explanation:

To calculate percent composition, you must:

- Calculate the molar mass.

- Divide the subtotal for each element's mass by the molar mass.

- Convert to a percentage

With that being said, given LiBr (Lithium Bromide), calculate the molar mass:

Lithium has an atomic weight of 7, and there is one Lithium atoms in LiBr. Bromine has an atomic weight of 80, and there is one Bromine atom in LiBr:

1(7)\\1(80)

Add the two products:

80+7

=87

The molar mass of LiBr is about 87 grams.

With that information, divide the subtotal of Lithium by the molar mass, and then multiply by 100 to convert to a percentage:

\frac{7}{87} × 100=

8.0459%

(Round to nearest percentage):

8%

Therefore, the percent composition of Lithium in the compound Lithium Bromide is about 8%.

Now, divide the subtotal of Bromine by the molar mass, and then multiply by 100 to convert to a percentage:

\frac{80}{87} × 100=

91.9540

(Round):

92%

Therefore, the percent composition of Bromine in the compound Lithium Bromide is about 92%.

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