False because the atoms are what helps the liquid in the container
Answer:
Please find the ten balanced equations below
Explanation:
According to the question, a balanced equation must contain equal number of atoms on both sides of the equation. To balance an equation, coefficients are used. The following are the balanced equation:
1. C + O2 → CO2 (balanced)
2. 2H2 + O2 → 2H2O (balanced)
3. 2Na + 2H2O → 2NaOH + H2 (balanced)
4. 4Na + O2 → 2Na2O (balanced)
5. 2Na + Cl2 → 2NaCl (balanced)
6. NaOH + HCl → NaCl + H2O (balanced)
7. NaOH + HNO3 → NaNO3 + H2O (balanced)
8. 2NaOH + H2SO4 → Na2SO4 + 2H2O (balanced)
9. Na2CO3 + 2HCl → 2NaCl + H2O + CO2 (balanced)
10. 2NaOH + CO2 → Na2CO3 + H2O (balanced)
When the order n of the reaction rate is determined by this formula:
rate = K * [A]^n
when we have the unit of rate M S^-1
and the unit of [A] M
So:
1- for k = 8.79 x 10^2 M S^-1 :
when the unit of K here is M S^-1
by substitution in rate formula:
M S^-1 = M S^-1 * M ^n
∴ M^n = 1
∴M^0 = 1
∴ this reaction rate is zero order reaction
2- when k = 4.46 x 10^-1 and has unit M-1 S-1:
by substitution in rate formula:
M S^-1 = M-1 S-1 * M^n
∴M^2 = M^n
∴n = 2 so this is the second order reaction
3- when K 2.35 x 10^6 and it's unit is S-1 :
So by substitution in rate formula:
M S^-1 = S^-1 * M^n
∴ M^n = M
∴ n = 1
So this is the first order reaction
4- when k = 1.88 x 10^-3 and its unit is M-2 S-1
by substitution in rate formula:
M S^-1 = M^-2 S^-1 * M^n
∴ M^n = M^3
∴ n = 3
∴ this is a third order reaction
from 1 & 2 & 3 & 4
so we can see that the correct answer is (4), K= 1.88 x 10^-3 M-2 S-1 is the highest order reaction.
