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seraphim [82]
3 years ago
15

A mass of 70.0kg on earth, what would their mass be on the moon, which has 1/6 the gravity of earth

Chemistry
1 answer:
zheka24 [161]3 years ago
5 0

Answer:

70 kg

Explanation:

We are given;

  • Mass on the earth = 70 kg
  • Gravity on the moon = 1/6 earth's gravity

We are required to determine the mass on the moon's surface.

We need to know that the mass of an object remains constant and is not affected by the gravitational pull of a surface.

Therefore, and object with a mass of 70 kg on the surface of the earth will still have the same mass on the surface of the moon.

Therefore, the mass on the moon's surface will still be 70 kg

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3 years ago
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Softa [21]

Water and sodium oxide have different properties because of their nature as explained below.

<h3><u>Explanation:</u></h3>

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3 years ago
Which expression represents a reaction rate?a. time/massc. energy/timeb. number/timed. time/energy
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3 years ago
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The bomb that destroyed tje Murrah Federal Office Building in Oklahoma City in April 1995 was constructed from ordinary material
Leto [7]

Answer:

ΔH⁰(11.4g NH₄NO₃) = -30.59Kj (4 sig. figs. ~mass of  NH₄NO₃(s) given) (exothermic)

Explanation:

           3NH₄NO₃(s) + C₁₀H₂₂(l) + 14O₂(g) => 3N₂(g)  +  17H₂O(g)   +  10CO₂(g)

ΔH⁰(f):  3(-365.6)Kj     1(-301)Kj    14(0)Kj       3(0)Kj    17(-241.8)Kj    10(-393.5)Kj

            = -1096.8Kj     = -301Kj     = 0Kj         = 0Kj      = -4110.6Kj    = -3930.5Kj

ΔHₙ°(rxn) = ∑ (ΔH˚(f)products) - ∑(ΔH˚(f)reactants)

= [3(0)Kj + 17(-241.8)Kj + (-393.5)Kj] - [(-(1096.8)Kj + (-301)Kj + (0)Kj]

= [-(8041.1) - (-1397.8)]Kj

= -6643.3Kj (for 3 moles NH₄NO₃ used in above equation)  

∴ Standard Heat of Rxn = -6643.3Kj/3moles = -214.8Kj/mole NH₄NO₃(s)

ΔH°(rxn for 14.11g  NH₄NO₃(s)) = (11.4g/80.04g·mol⁻¹)(-214.8Kj/mol) = 30.5937Kj ≅ 30.59Kj (4 sig. figs. ~mass of  NH₄NO₃(s) given)

5 0
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