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Dmitry [639]
2 years ago
12

In the scientific article, "Not-So-Tiny Bubbles," there are two main concepts discussed Decompression and how gasses dissolve in

liquids. How are these concepts related to each other, according to the article? Try explaining that relationship in your own words​
Chemistry
2 answers:
Hatshy [7]2 years ago
7 0

Answer:

when a gas dissolves in a liquid, it causes decompreession

Decompression causes the gas in a liquid to expand.

lana [24]2 years ago
7 0

Answer:

answer gas liquid and shenova

Explanation:

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Arte-miy333 [17]

Answer:

0.89kg

Explanation:

Q=mL L=specific latent heat

Q=energy required in J

m=mass in Kg

Q=mL

m=Q/L

m=2000000J/2.25 x 10^6 J kg-1

m=0.89kg

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A sample of granite contains various oxides of silicon, aluminum, sodium, potassium, calcium, and iron. each of these oxides giv
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CdF2(s)⇄Cd2+(aq)+2F−(aq)A saturated aqueous solution of CdF2 is prepared. The equilibrium in the solution is represented above.
kupik [55]

Answer:

The correct answer is option a.

Explanation:

CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)

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Equilibrium concentration fluoride ions = [F^{-}]=0.117 M

Molar solubility is the maximum concentration of salt present in water in ionic form beyond that no more salt will exist in its ionic form and will settle down in bottom of the solution.

The molar solubility of the solid cadmium fluoride = 0.0585 M

CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)..[1]

NaF(s)\rightleftharpoons Na^{+}(aq)+F^-(aq)

Due to addition of sodium fluoride will increase concentration of fluoride in the solution.And due to common ion effect the equilibrium will shift in backward direction in [1], that is precipitation of more cadmium fluoride.

Hence, decrease in solubility will be observed.

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According to the following reaction, how many moles of oxygen gas are necessary to form 0.408 moles carbon dioxide?
Neporo4naja [7]

Answer:

2 molecules of oxygen are necessary

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Molybdenum (Mo) crystallizes with a body-centered cubic lattice and has an atomic radius of 136.1 pm.
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