To answer this question I would have to know the elements in the compound
The formula for molarity is: mol/L. so it would be 2.0 mol/ 6.0 L.
the answer is: .33 M
hope this helps!
Answer:
Mole fraction for solute = 0.1, or 10%
Molality = 6.24 mol/kg
Explanation:
22.3% by mass → In 100 g of solution, we have 22.3 g of HCOOH
Mass of solution = 100 g
Mass of solute = 22.3 g
Mass of solvent = 100 g - 22.3g = 77.7 g
Let's convert the mass to moles
22.3 g . 1mol/ 46 g = 0.485 moles
77.7 g. 1mol / 18 g = 4.32 moles
Total moles = 4.32 moles + 0.485 moles = 4.805 moles
Xm for solute = 0.485 / 4.805 = 0.100 → 10%
Molality → mol/ kg → we convert the mass of solvent to kg
77.7 g. 1 kg / 1000g = 0.0777 kg
0.485 mol / 0.0777 kg = 6.24 m
Answer:
In doubling the concentration of the alkyl halide, the reaction rate also increases two-fold. However, doubling the concentration of the nucleophile does not in any way alter the reaction rate. Thus, the reaction rate is proportional only to the alkyl halide's concentration.
Resonance, leaving group, carbonyl carbon delta+, and steric effect is the most crucial variables that affect the relative reactivity of a functional group containing a carbonyl in an addition or substitution process.
Discussion:
1. Carbonyl Carbon Delta+: The carbonyl group becomes more electrophilic and accelerates nucleophilic assault when the carbonyl carbon delta+ is bigger.
2. Resonance: When the carbonyl is transformed into the tetrahedral adduct, it may be lost. Loss of resonance increases the energy of the transition state for this nucleophilic assault because resonance has the function of stabilizing. Therefore, a carbonyl functional group's resistance to nucleophilic attack increases as resonance in the group increases in importance.
3. Leaving group: Tetrahedral adduct fragmentation is encouraged by a better LG.
4. Steric effects: The nucleophilic attack on carbonyl carbon is delayed when sterically impeded.
Learn more about carbonyl here:
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