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miv72 [106K]
3 years ago
11

If one mole (1.00 mol) of copper (Cu) has 6.02x10^23 atoms of copper, how many molecules are in 1.00 mol of nitrogen gas (N2)

Chemistry
1 answer:
sveta [45]3 years ago
5 0
WAS IT C??? CANT BE FOR SURE

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When would you want to be at the beach during a spring tide?
meriva
I would want to be at the beach during the spring.
8 0
3 years ago
A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati
Katen [24]

Answer:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

Explanation:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}

The pKa is

-Log (Ka) = -Log (6.2x10^{-8}) = 7.2

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1)  moves to the left neutralizing the excess proton concentration.

3 0
3 years ago
What is the molarity of a solution that contains 20 grams of CaBr2<br> in 0.50 liter of solution?
ELEN [110]

Answer:

2 M

Explanation:

mole weight of CaBr2 = 40 + 2 * 79.9 = 199.8 gm

20 gm is then   20/199.8 =.1 mole

.1 mole / .50 liter = 2 M

8 0
1 year ago
What is the empirical formula for a compound which is composed of 31.9 g of Mg and 27.1 g P?​
ahrayia [7]

Answer:

Answer is on the pic

Explanation:

I hope it's helpful!

3 0
2 years ago
An aqueous solution at 27°c contains 3.6 g of a protein in a 200 ml sample. the osmotic pressure is 0.0203 atm. what is the mola
umka21 [38]
In order to calculate the molar mass of the protein, we may manipulate the ideal gas equation:
PV = nRT, where n is the number of moles. We also know that:
n = m / Mr, where m is mass and Mr is molecular weight
Thus,
Mr = (mRT)/(PV)
Here, the mass is in grams, the temperature is in Kelvin, the pressure is in atm and the volume is in liters, so the molar gas constant is 0.082057.

Mr = (3.6 * 0.082057 * (27 + 273)) / (0.0203 * 0.2)
Mr = 21,828 g/mol
Thus, the Mr of the protein is 2.18 x 10⁴ g/mol
8 0
3 years ago
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