Answer:
Final pressure is 1.42atm
Explanation:
Based on Gay-Lussac's law, pressure of a gas is directely proportional to its absolute temperature. The equation of this law is:
P₁T₂ = P₂T₁
<em>Where P is pressure and T is absolute temperature of 1, initial state and 2, final state of the gas.</em>
In the problem, initial conditions are Standard Temperature and Pressure, STP, that are 1 atm and 273.15K.
If the final temperature is 115°C = 388.15K (115°C + 273.15 = 388.15K), using Gay-Lussac's law:
P₁T₂ = P₂T₁
1atmₓ388.15K = P₂ₓ273.15K
1.42atm = P₂
<h3>Final pressure is 1.42atm</h3>
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