What is the first thing you should do when any accident occurs during a science

Chemistry

2 answers:

STatiana [176]2 years ago

7 0

I never understand these questions so let’s just look at them logically

Leaving the room: Makes enough sense, in the event that the “accident” is lethal, you don’t really want to be there.

Calling the paramedics: I feel like this is an overreaction, the “accident” might not even be serious

Locate the first aid kit: Also in the same vein as paramedics, what are the chances that the accident causes harm

Call a teacher: They should know what to do, or at least, they’re the “adults”, so that’s probably your best bet

Lena [83]2 years ago

5 0

Answer:

Tell your teacher or learning coach.

Explanation:

It is always best to let an experienced teacher or coach know what has happened, so they may address it carefully and correctly.

Hope this helps : )

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Express 749 000 000 in scientific notation,

Dima020 [189]

Answer:

7.49 × 108

Explanation:

Scientific notation is a way to express numbers in a form that makes numbers that are too small or too large more convenient to write. It is commonly used in mathematics, engineering, and science, as it can help simplify arithmetic operations. In scientific notation, numbers are written as a base, b, referred to as the significant, multiplied by 10 raised to an integer exponent, n, which is referred to as the order of magnitude:

8 0

2 years ago

How many grams of Fe2+ are there in 0.003109 moles of Fe2+?

Sergio [31]

Answer: 0.174 g

Explanation:

First of all understand that charge on an atom like here 2+ will not vary molar mass. because ions are formed by loss or gain of electrons and electrons do not contribute to the mass of an atom or ion. so losing or gaining electron doesnt create any difference.

molar mass of Fe, i.e. mass of 1 mole of Fe is 56 g. So, mass of 1 mole of Fe2+ will also be 56 g.

given is 0.003109 moles of Fe2+,

Use maths,

1 mole of Fe2+ weighs 56 g

So, 0.003109 moles will weigh = (56 g / 1 mol ) x 0.003109 = 0.174 g.