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Andreyy89
3 years ago
5

How much time will it take a car travelling at 88 km/hr (55mi/hr)to travel 500km?

Chemistry
1 answer:
dybincka [34]3 years ago
7 0
The time it will take for a car travelling 88 km/hr (55mi/hr) to travel 500km would be 3.5 hours.

How? Add 88 + 58.

That'll equal 143, then divide 500 ÷ 143 = 3.5

So, 3.5 is the time that the car will take travelling 88 km/hr trying to reach the destination of 500km.
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How much heat is needed to raise the temperature of water with mass of 27.0 g at 20.0°C to 45.0°C?
ohaa [14]

Answer:

2835 J

Explanation:

Take the specific heat capacity of water as 4.2 J/ g°C.

Energy (heat) = mass x specific heat capacity x change in temperature

(E= mcΔT)

E = 27 x 4.2 x (45-20)

E = 2835 J

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3 years ago
Predict: Will a 1500 kg car moving at the same speed as the tennis ball have
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4 0
3 years ago
PLEASE ANSWER FAST
Elis [28]

First we need to calculate the number of moles of FeS_{2}:

number of moles = mass (grams) / molecular mass (g/mol)

number of moles of FeS_{2} = 198.2/120 = 1.65 moles

From the chemical reaction we deduce that:

if            4 moles of FeS_{2} produces 8 moles of SO_{2}

then  1.65 moles of FeS_{2} produces X moles of SO_{2}

X = (1.65×8)/4 = 3.3 moles of SO_{2}

Now we can calculate the mass of SO_{2}:

mass (grams) = number of moles × molecular mass (grams/mole)

mass of SO_{2} = 3.3×64 = 211.2 g

7 0
3 years ago
In Scratch, when making the jump command for a sprite to jump if the space bar is pressed, you place the command outside the hex
Rzqust [24]

Answer:

that would be true you place it outside the hexagon

Explanation:

6 0
2 years ago
The specific heat of copper metal is 0.385 J/(g × °C). How much energy must be added to a 35.0 gram sample of copper to change t
Montano1993 [528]
Q = mC∆T 

<span>where: </span>
<span>q = heat </span>
<span>m = mass of substance = 35.0 grams </span>
<span>C = 0.385 J/g*C </span>
<span>∆T = change in temperature = 65C - 20C = 45C </span>

<span>q = (35.0 g)*(0.385 J/g*C)*(45C) = 606 J </span>
3 0
3 years ago
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