Answer :
The steps involved in the electron-dot structure of given molecule are :
Step 1 : First we have to determine the total number of valence electron in a molecule.
Step 2 : Draw the skeleton of the molecule.
Step 3 : Placing a bonding pair of electrons between the atoms to form the chemical bonds.
Step 4 : The rest of the electrons are used as a lone pair for central or terminal atoms to achieve an octet to finish the electron-dot structure.
All the electron-dot diagram of given molecule is shown below.
Answer: c extracting oil
Explanation:
Saudi Arabia is known for there huge oil market
Answer:
see explanation below
Explanation:
First, you are not providing any data of the bromide solution to calculate the mass. So, in order to help you, I will take some random values from a similar exercise, so you can solve this later with your data.
Let's suppose you add 360 mL of a 1.45 mol/L of a calcium bromide solution into the flask. To calculate the mass it was added, you need to calculate first the moles added. This can be done with the following expression:
M = n/V
Where:
M: molarity of solution
n: moles of solution
V: volume (in liters) of solution
here, you have to solve for n, so:
n = M*V
replacing the above data you have:
n = 1.45 * (0.360) = 0.522 moles
Now that we have the moles, you can calculate the mass by the following expression:
m = n * MM
Where MM it's the molar mass of calcium bromide. The reported MM of calcium bromide is 199.89 g/mol, so replacing:
m = 199.89 * 0.522
m = 104.34 g
And this is the mass that was added of the solution. As I stated before, use your data in this procedure, and you should get an accurate result.
Answer:
AT THE END OF 80% DISSOLUTION, THE PRESSURE OF NO2 HAS CHANGED FROM 99kPa TO 139.97kPa
Explanation:
P1 = 99 kPa
P2 = unknown
From the reaction,
2 mole of NO2 will produce 2 mole of NO
We can also say that 1 mole of NO2 will produce 1 mole of NO
At 56.6 % of NO2, 0.566 mole of NO2 will be consumed
At STP, 1 mole of a substance will occupy 22.4 dm3 volume
0.566 mole will occupy ( 22.4 * 0.566 / 1) dm3 volume
= 39.58 dm3 volume
V1 = 39.56 dm3
At the new percent of 80%, 0.80 mole of NO2 will be consumed
Since, 1 mole = 22.4 dm3
0.80 mole = (22.4 / 0.80) dm3
= 28 dm3
V2 = 28 dm3
Using the equation of Boyle's law which shows the relationship between pressure and volume of a given mass of gas at constant temperature, we have:
P1 V1 = P2 V2
Re-arranging to make P2 the subject of formula:
P2 = P1V1 / V2
P2 = 99 kPa * 39.56 / 28
P2 = 3916.44 kPa / 28
P2 = 139.87 kPa
So at 80 % dissociation of NO2, the pressure has changed from 99 kPa to 139.97 kPa.