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artcher [175]
3 years ago
8

A 350.0 ml sample of gas has a temperature of 22.7 C and a pressure of 0.914 atm. What temperature would be needed for the same

amount of gusto fit into a 220.0 mL flask at standard pressure? (amount of moles is held constant)
Chemistry
1 answer:
Rus_ich [418]3 years ago
7 0

Answer:

Explanation:

We shall apply gas law formula

P₁ V₁ / T₁ = P₂V₂ / T₂

.914  x 350 / ( 273 + 22.7 ) = 1 x 220 / T₂

1.0818 = 220 / T₂

T₂ = 203.36 K

= - 69.64 ⁰ C

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As molal concentration rises, so does freezing point depression. It can be expressed mathematically as ΔTf = Kfm.

<h3>What is Colligative Properties ?</h3>
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5 0
1 year ago
How does shaking or stirring a mixture of solute and solvent affect a solution?
MA_775_DIABLO [31]
I know this one it’s B
3 0
2 years ago
C is the element symbol for which element?<br>a. Carbon<br>b. Cadmium<br>c. Celenium<br>d. Chlorine​
il63 [147K]

Answer:

A) Carbon

Explanation:

the others are wrong its A

6 0
2 years ago
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Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B Mass ratio A/B =
LUCKY_DIMON [66]

Answer:

mass ratio of A/B is 2:1

Explanation:

Since the mass of box A = 10g

                mass of box B = 5g

   Mass of box C = mass of box A + mass of box

A ratio compares two quantities. To find the ratio of the two boxes:

  Ratio of A to B = \frac{mass of A}{mass of B}

  Ratio of A to B = \frac{10grams}{5grams} = 2

The mass ratio is 2:1 i.e box A has twice the mass of B

8 0
3 years ago
Predict the density of acetylene gas (C2H2) at 0.910 atm and 20oC.
zhuklara [117]

Answer:

d = 0.98 g/L

Explanation:

Given data:

Density of acetylene = ?

Pressure = 0.910 atm

Temperature = 20°C (20+273 = 293 K)

Solution:

Formula:

PM = dRT

R = general gas constant = 0.0821 atm.L/mol.K

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0.910 atm × 26.04 g/mol = d × 0.0821 atm.L/mol.K×293 K

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d = 23.7  atm.g/mol / 24.1 atm.L/mol

d = 0.98 g/L

6 0
3 years ago
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