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artcher [175]
3 years ago
8

A 350.0 ml sample of gas has a temperature of 22.7 C and a pressure of 0.914 atm. What temperature would be needed for the same

amount of gusto fit into a 220.0 mL flask at standard pressure? (amount of moles is held constant)
Chemistry
1 answer:
Rus_ich [418]3 years ago
7 0

Answer:

Explanation:

We shall apply gas law formula

P₁ V₁ / T₁ = P₂V₂ / T₂

.914  x 350 / ( 273 + 22.7 ) = 1 x 220 / T₂

1.0818 = 220 / T₂

T₂ = 203.36 K

= - 69.64 ⁰ C

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What is a solution of zinc and copper?<br>five letter word
Lana71 [14]

Answer:

Brass

Explanation:

Brass is an alloy of copper and zinc, in proportions which can be varied to achieve varying mechanical and electrical properties.

5 0
2 years ago
A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th
mote1985 [20]

Explanation:

The given data is as follows.

Solvent 1 = benzene,          Solvent 2 = water

 K_{p} = 2.7,         V_{S_{2}} = 100 mL

V_{S_{1}} = 10 mL,       weight of compound = 1 g

       Extract = 3

Therefore, calculate the fraction remaining as follows.

                  f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}

                                  = [1 + 2.7(\frac{100}{10})]^{-3}

                                  = (28)^{-3}

                                  = 4.55 \times 10^{-5}

Hence, weight of compound to be extracted = weight of compound - fraction remaining

                                  = 1 - 4.55 \times 10^{-5}

                                  = 0.00001

or,                               = 1 \times 10^{-5}

Thus, we can conclude that weight of compound that could be extracted is 1 \times 10^{-5}.

7 0
3 years ago
Read 2 more answers
At what point is base no longer added during a titration
maria [59]
When you doing a titration, you need to use an indicator to confirm whether the reaction is completed. When the indicator has the color change and will not change back in one minute, the reaction is finished and you don't need to add more.
8 0
3 years ago
Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ΔH° for the r
PolarNik [594]

Answer: -105 kJ

Explanation:-

The balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times B.E(reactant)]-\sum [n\times B.E(product)]

\Delta H=[(n_{N_2}\times B.E_{N_2})+(n_{H_2}\times B.E_{H_2}) ]-[(n_{NH_3}\times B.E_{NH_3})]

\Delta H=[(n_{N_2}\times B.E_{N\equiv N})+(n_{H_2}\times B.E_{H-H}) ]-[(n_{NH_3}\times 3\times B.E_{N-H})]

where,

n = number of moles

Now put all the given values in this expression, we get

\Delta H=[(1\times 945)+(3\times 432)]-[(2\times 3\times 391)]

Delta H=-105kJ

Therefore, the enthalpy change for this reaction is, -105 kJ

8 0
3 years ago
two people start out 100 meters apart from each other and start moving towards each other at the same time. One person is moving
andreev551 [17]

Answer:

1.332 meters per second. // 2.664 meters per second.

Explanation:

the slower person moved 33.3 meters, and the faster person moved 66.6 meters.

the slower person is moving 33.3 meters in 25 seconds, while the other person is moving 66.6 meters in 25 seconds

slower person moved 33.3/25 = 1.332 meters per second.

faster person moved 66.6/25 = 2.664 meters per second.

4 0
3 years ago
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