Answer:
15mg/ml
Step-by-step explanation:
Percent mass per volume ( % m/v) is unit expression that tells us how many grams of a solute that we can find 100 ml of a particular solution.
In the above question, we are asked to express 1.5%w/v Bepotastine besilate (BEPREVE) ophthalmic solution as mg/mL
Step 1
1.5% w/v = 1.5 g of Bepotastine besilate (BEPREVE) in 100ml ophthalmic solution
Hence, if
100ml = 1.5g
1 ml = y g
We Cross Multiply
100ml × yg = 1 ml × 1.5g
yg = 1 ml × 1.5g/100ml
= 0.015g
Therefore, in 1 ml we have 0.15 g.
Step 2
Since we are asked to express as mg/ml
We convert 0.015g to mg
1 gram = 1000 milligrams
0.015 grams =
Cross Multiply
0.015grams × 1000 milligrams/ 1 gram
= 15 mg
Therefore, the concentration in mg/ml of 15% m/v of Bepotastine besilate (BEPREVE) ophthalmic solution is 15mg/ml
This question is asking for the value of two numbers, which we can label as:
#1 = x
(Any value we do not know can be represented with a variable)
#2 = 3x + 2
("2 more" means + 2, and "3 times" means multiply by 3. The "another" is the variable we talked about before. Combining everything we have 3x + 2).
The last piece of information we are given is that the sum of the two numbers is 22. The word sum indicates that we need to add the two numbers, and when they added they will equal the integer 22.
(x) + (3x + 2) = 22
x + 3x + 2 = 22
Combine like terms
4x + 2 = 22
Subtract 2 from both sides
4x = 20
Divide 4 from both sides
x = 5
This sole value of "x" already gives us the value of the first number. Since our second number is "3x + 2", all we have to do is plug in the value of x into the expression.
3x + 2 = 3(5) + 2 = 15 + 2 = 17
The second number is 17.
Final Answer: The two numbers are 5 and 17.
(If you want to check, add the two numbers and make sure they add up to 22 and multiply 5 by 3 and add 2.)
You would subtract 52-7 and your answer would be 45
A. 6(k + s)
It's the distributive property.
Answer:
The answer's B.
Step-by-step explanation:
I just took the test.
Quadrilateral EFGH is the only quadrilateral that fits the specifications for a kite. A kite has two pairs of adjacent sides that are congruent and opposite sides that are not congruent.
