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Nimfa-mama [501]
3 years ago
10

PLEASE HELP ! Which logarithmic graph can be used to approximate the value of y in the equation 4^y = 8?

Mathematics
1 answer:
Schach [20]3 years ago
5 0
4^y=x
log(4^y)=logx
y*log4=logx
y=logx/log4
so, this is a log function, so it is not B,
vertical asymptote for this function is 0, so it did not move right or left (the graph will be look like log x), correct answer is C
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stiv31 [10]

Answer:

-1/4 , -1

Step-by-step explanation:

I solved it using Factorization method and Quadratic Equation .

Factorization Method

4x^2+5x+1=0\\Write +5x- as- a -difference(write+5x-using- two- numbers -in-which-their-sum-is ; 5-and-their-product-is ; 4)\\4x^{2} +4x+1x+1=0\\Factorize-out-common-terms\\4x(x+1)+1(x+1)=0\\Factor-out-(x+1)\\(4x+1)(x+1)=0\\4x+1 =0    \\x+1=0\\4x=0-1\\x =0-1\\4x =-1\\x =-1\\4x=-\frac{1}{4} \\\\Answer = -1/4 , -1

Quadratic Equation

4x^2+5x+1=0\\a = 4\\b =5\\c = 1\\\\x =\frac{-b\±\sqrt{b^2 -4ac} }{2a} \\\\x = \frac{-(5)\±\sqrt{(5)^2-4(4)(1)} }{2(4)} \\\\x = \frac{-5\±\sqrt{25-16} }{8} \\\\x = \frac{-5\±\sqrt{9} }{8} \\\\x = \frac{-5\±3}{8} \\\\x =\frac{-5+3}{8} \\\\x = \frac{-5-3}{8} \\\\x = \frac{-2}{8} \\\\x = \frac{-8}{8} \\\\x = -\frac{1}{4} \\x=-1

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3 years ago
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wlad13 [49]

One solution was found :  t ≤ -13 (number 4)

Pull out like factors :

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Divide both sides by  -3  

Remember to flip the inequality sign:  

Solve Basic Inequality :

Subtract  13  from both sides to get t≤−13

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