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3 years ago

15

To isolate a single variable when rearranging equations, move all other variables to the _________of the equation by using _

_______on them and remembering to perform that operation __________ Make sure the rearrangement has the target variable__________

1 answer:

noname [10]3 years ago

5 0

Answer:

Other side, the opposite function, on both sides of the equation, in the numerator, not the denominator

Step-by-step explanation:

To isolate a single variable when rearranging equations, move all other variables to the other side of the equation by using the opposite function on them and remembering to perform that operation on both sides of the equation. Make sure the rearrangement has the target variable in the numerator, not the denominator.

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Find three consecutive integers whose sum is 51

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1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

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A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

<em /> $L \to$ <em> Letters</em>

<em /> $C \to$ <em> Cost</em>

<em />

Using proportional reasoning, we have:

$C = kL$

Where

<em /> $k \to$ <em> ratio of proportion</em>

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

<u>When C = 6.75, we have:</u>

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

<u>When L = 7, we have:</u>

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

<u>When L = 1, we have:</u>

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

<u>When L = 500, we have:</u>

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

<u>When C = 18.90, we have:</u>

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Read more about proportions at:

brainly.com/question/21126582

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