Answer:
n squared + 3n + 1
Step-by-step explanation:
5,11,19,29
Firstly look at the difference between each number. The first difference is 6 then 8 then 10 etc. After that you look at your created sequence - 6,8,10 etc. The difference is 2 each time. Then applying rules, you have to do the constant difference divided by 2 to get a coefficient of n squared. So in this case it's n squared because 2/2 = 1 so you don't have to place a 1 in front of the n squared. After you create a sequence from the n squared. That would be 1,4,9 etc. Then you need to see how to get from the sequence: 1,4,9 etc to your original sequence: 5,11,19 etc. So if you calculate it you will get 4,7,10 because firstly 5-1 = 4 then 11-4 = 7 etc. The sequence 4,7,10 is a linear sequence so the constant difference is 3 each time. So to get a nth term of a linear sequence you will start off as 3n then you will substitute 1 then 2 then 3 into the 3n. Therefore that would be 3,6 etc. So if you take the first substituted term, that would be 3 as said before then you will have to see how to get from the 3 to 4 so that is just adding 1. So the nth term of this linear sequence is 3n + 1. Check if it works at the end. So the overall nth term of the quadratic sequence is n squared as said before + 3n + 1.
Answer: I forgot i remember the answer in my head I forgot..
Step-by-step explanation:
Answer:
x ≤
Step-by-step explanation:
So first you would start by getting rid of the -4. To get rid of -4, you would need to + 4 on each side leaving you with -2x ≤ 15. Now you need to get rid of -2 from x so that would convert equation to x ≤ . Hoped it helped!
⭐ Answered by Foxzy0⭐
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Answer:
Two different transformations happen. Rotation/Reflection and translation (I say rotation/reflection because they can both put the parabola where it is after being transformed)
(Rotation- 180 degrees)
(Reflection across its it's starting point)
Translation- pushed up 4 points from negative 4 to 0 on the y-axis
When you put the parent function into a graph it is positive so the u is opening upward and starts at -4. Both sides of the u go through the points (0,0)and (4,0).
But in the transformed function is negative so the u opens downward. The sides going through the points (0,-4) and (4,-4)
I hope this makes sense