Question

Find the distance between the two points (2,5) and (6,-1)

Answer 1

Answer:

= $\sqrt{52}$ units

Step-by-step explanation:

x₁ = 2 ; y₁ = 5

x₂ = 6 ; y₂ = -1

D = $\sqrt{(x₂ - x₁)² + (y₂ - y₁)²}$

   =$\sqrt{(6 - 2)² + (-1 -5)²}$

   =$\sqrt{4² + (-6)²}$

   = $\sqrt{16 + 36}$

D = $\sqrt{52}$ units

Answer 2

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(6-2)^2+(-1-5)^2}\implies d=\sqrt{4^2+(-6)^2} \\\\\\ d=\sqrt{16+36}\implies d=\sqrt{52}\implies d=2\sqrt{13}$