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Lena [83]
3 years ago
11

ABCO is the image of ABCD What transformation(s) would result in this image?

Mathematics
1 answer:
Monica [59]3 years ago
7 0

Answer:

D. ABCD is rotated 180° around the origin

Step-by-step explanation:

The formula for an 180° rotation around the origin is (-x, -y).

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Solve the formula a(m-r) + t =s for a.
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Step-by-step explanation:

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3 years ago
Find the angle of elevation of the sun from the ground to the top of a tree when a tree that is 10 yards tall casts a shadow 14
Hitman42 [59]

Answer:

The angle of elevation of the sun from the ground to the top of a tree is 36^{\circ}.

Step-by-step explanation:

As given

The sun from the ground to the top of a tree when a tree that is 10 yards tall casts a shadow 14 yards long.

Now by using the trignometric identity .

tan\theta =\frac{Perpendicular}{Base}

As figure is  given below .

AB =  Perpendicular = 10 yards

BC =  Base = 14 yards

Putting all the values in the trignometric identity .

tan\theta =\frac{AB}{BC}

tan\theta =\frac{10}{14}

\theta =tan^{-1}(\frac{10}{14})

\theta =36^{\circ}

Therefore the angle of elevation of the sun from the ground to the top of a tree is 36^{\circ}.

7 0
3 years ago
Read 2 more answers
Is there a faster way to find GCF of large numbers e.g 828 and 529.
Sunny_sXe [5.5K]
You can use prime factorization to find the GCF of a set of numbers. This often works better for large numbers, where generating lists of all factors can be time-consuming.
Here’s how to find the GCF of a set of numbers using prime factorization:
* List the prime factors of each number.
* Circle every common prime factor — that is, every prime factor that’s a factor of every number in the set.
* Multiply all the circled numbers.
The result is the GCF.
For example, suppose you want to find the GCF of 28, 42, and 70. Step 1 says to list the prime factors of each number. Step 2 says to circle every prime factor that’s common to all three numbers (as shown in the following figure).
As you can see, the numbers 2 and 7 are common factors of all three numbers. Multiply these circled numbers together:
2 · 7 = 14
Thus, the GCF of 28, 42, and 70 is 14.

5 0
2 years ago
How is the quotient 80,000÷2000 different from the quotient 80,000÷200 or 80,000÷20
Olegator [25]
 2,000, 200 and 20 are similar except for the number of zeros.
You can remove a zero from each to equal the number of zeros in the divisor.  So 80,000 ÷ 2,000 is equivalent to 80 ÷ 2 = 40  you just remove the 3 zeros
80,000 ÷ 200 is equivalent to 800 ÷ 2 = 400 you just keep removing 0s like for instance this time it was 2 lastly 80,000 ÷ 20 only allows us to remove 1 zero 8,000 ÷ 2 = 4,000. The smaller the divisor the greater the quotient when dividing the same number like for instance in this example 80,000
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