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iren2701 [21]
3 years ago
13

Help me out pleasssssssssssssssss

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0

Answer: $2.34

All you do is multiply 39 cents (.39) times how many letters you want to send (6), and that is your answer.

Hope this helps. :)

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Which one got infinite solutions
GalinKa [24]
I think C I’m just in high school so don’t get mad if is wrong I’m good in math tho
5 0
3 years ago
Anna is writing a computer game program. She needs to “move” a square 3 units to the left and 2 down by applying a translation r
Nadya [2.5K]

Answer:

(-3,-2), (-3,2) , (1,2) and (1,-2)

Step-by-step explanation:

Give the translation rule as; 3 units to the left and 2 units down, it means (-3,-2)

The given coordinates of the square are (0,0) and (4,4). You can plot the coordinates on a graph tool and determine the position of the other vertices

of the square as (0,4) and (4,0)

Applying the translation to each point

(0,0)⇒(-3,-2) = (-3,-2)

(0,4)⇒(-3,-2) = (-3,2)

(4,4)⇒ (-3,-2) = (1,2)

(4,0)⇒(-3,-2)= (1,-2)

The image of the vertices after transformation will be

(-3,-2), (-3,2) , (1,2) and (1,-2)

8 0
3 years ago
To multiply a sum by a number, multiply each term inside the parentheses by the number outside the parentheses.
astra-53 [7]
Numberical expression
8 0
3 years ago
8n-2(3n-3)=-2(-n-3) what is n<br> please show work
Galina-37 [17]

Answer:

0

Step-by-step explanation:

8n-2(3n-3)= -2(-n-3)

8n-6n+6=2n+6

2n+6=2n+6

2n=2n+6-6

2n=2n

Check

8(0)-2(3(0)-3)=-2(-0-3)

6=6

5 0
4 years ago
A cylinder shaped can needs to be constructed to hold 300 cubic centimeters of soup. The material for the sides of the can costs
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

Cost = Area Cylinder body* cost * 0.03 cm^3 + Area of 2 lids*cost 0.06 of cm^3

Volume = 300 cm^3

Volume = Base *h  

Volume = pi * r^2 * h = 300

h = 300/(pi * r^2 )

Area material =  2*pi * r * h * 0.03 + 2 pi r^2 * 0.06

Area material = 0.06*pi * r * 300/(pi* r^2) + 0.12 * pi * r^2

dmaterial/dr = (-1)18 r^-2 + 0.12 pi * 2*r

dmaterial/dr = -18 r^-2 + 0.24 pi * r

The minimum occurs when the right side = 0

18/r^2 = 0.24 *pi r

18 = 0.24*pi * r^3

18/(0.24 * pi) = r^3

23.89 = r^3

cube root (23.89) = cuberoot(r^3)

r = 2.88 cm

h = 300/pi * r^2

h = 300/(3.14 * 2.88^2)

h = 11.52

This isn't much of a check but we can try it.

Volume = 3.14 * 2.88^2 * 11.52

Volume = 302.01 which considering all the rounding is pretty close.

Here's a graph that confirms my answer.

3 0
3 years ago
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