As is the case for any polynomial, the domain of this one is (-infinity, +infinity).
To find the range, we need to determine the minimum value that f(x) can have. The coefficients here are a=2, b=6 and c = 2,
The x-coordinate of the vertex is x = -b/(2a), which here is x = -6/4 = -3/2.
Evaluate the function at x = 3/2 to find the y-coordinate of the vertex, which is also the smallest value the function can take on. That happens to be y = -5/2, so the range is [-5/2, infinity).
Is either I’m blind and can’t see or the letter are way too small
Answer:
13.989 rounded to nearest tenth is 14.0.
Step-by-step explanation:
Answer:
28m⁷n⁵
Step-by-step explanation:
You would first multiply 14 by 2. You would then multiply (which is really addition when it comes to exponents) your like-term exponents.
(14m²n⁵)(2m⁵) =28m⁷n⁵
14(2) = 28
m² + m⁵=m⁷
n⁵ + 0 = n⁵