Write an equation in slope-intercept form for the line with slope 4/3 and -3 intercept .

Mathematics

1 answer:

mojhsa [17]3 years ago

4 0

Answer:

The equation would be y = 4/3x - 3

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which transformation causes the described change in the graph of the function y = cos x? the transformation results in a horizon

luda_lava [24]

The transformations that can occur to the graph of the function y = cos x that will exhibit changes would be changes to the angle, or changes to the coefficient. The transformations can be viewed as follows:

y = cos x transforms to y = cos (kx)

k > 1 ; a horizontal shrink occurs
0 < k < 1 ; a horizontal stretch occurs

y = cos x transforms to y = A cos x

|A| > 1 ; a vertical stretch occurs
|A| < 1 ; a vertical shrink occurs

5 0

3 years ago

70 pointsss for the correct answer

nignag [31]

Answer:

f(x) = 12x³ - 19x² + 17x - 17

Step-by-step explanation:

We can the numerator by multiplying the denominator by the quotient, and then adding the remainder.

We're given a denominator of 4x - 5

a quotient of 3x² - x + 3

and a remainder of -2

so the original numerator is:

(4x - 5)(3x² - x + 3) - 2

= 12x³ - 4x² + 12x - 15x² + 5x - 15 - 2

= 12x³ - 19x² + 17x - 17

Let's test that by dividing it by 4x -5 with long division:

$\ \ \ \ \ \ \ \ \ \ 3x^2 - x + 3\\4x - 5\overline{)12x^3 - 19x^2 + 17x - 17}\\.\ \ \ \ \ \ \ \ \ \underline{2x^3 - 15x^2}\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ -4x^2 + 17x\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \underline{-4x^2 + 5x} \\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 12x - 17\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \underline{12x - 15}\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2R$