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Musya8 [376]
3 years ago
14

Ethan this time can you show me how to place it in all 3 of my boxes

Mathematics
2 answers:
MaRussiya [10]3 years ago
8 0
Eqn is 4^n for the nth job

so for 9th it is

= 4^9

which is 4x4x4x4x4x4x4x4x4

= 262144

Nitella [24]3 years ago
7 0
Here, Equation: 4⁹

Fill 4 in first box which is base, and 9 in upper box which is exponent.

Evaluation: 4⁹ = 4 * 4 * 4 * 4 * 4 * 4 * 4 * 4 * 4

4⁹ = 1024 * 256 = 262144

In short, Your Answer would be: 262144 pennies

Hope this helps!
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10cm 3mm - 4.8cm<br> I do not understand that well can someone please help no need to explain
OleMash [197]

Answer:

60mm   or   6cm

Step-by-step explanation:

108mm - 48mm = 60mm

3 0
2 years ago
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Please help I have a sucky teacher and don’t know what to do
Katyanochek1 [597]

Answer:

  1, 4, 3, 6, 2, 7, 5

Step-by-step explanation:

The circle operator in f\circ g means that the function named on the left (f) operates on the result of the function named on the right (g). So, the notation

  (f\circ g)(x)

means

  f(g(x))

That is, g(x) is computed and used as input to the function f. When the function definitions are as shown, the evaluation proceeds in these steps.

  (f\circ g)(-4)\\\\=f(g(-4))\quad\text{write as function of a function}\\\\=f(-2(-4)^2)\quad\text{put -4 for x in $g(x)$}\\\\=f(-2(16))\quad\text{evaluate $(-4)^2$}\\\\=f(-32)\quad\text{evaluate $g(-4)$}\\\\=2(-32-1)\quad\text{put -32 for x in $f(x)$}\\\\=2(-33)\quad\text{first step evaluating $f(-32)$}\\\\=-66\quad\text{value of $(f\circ g)(-4)$}

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If your step choices at the bottom are numbered 1 to 7 left-to right, then the sequence is as shown in the Answer section above.

4 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
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Gennadij [26K]
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4 worksheets : 1 student
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3 years ago
Syd chooses two different primes, both of which are greater than $10,$ and multiplies them. The resulting product is less than $
Mars2501 [29]

Answer:

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Step-by-step explanation:

There are 7 primes between 10 and 35: 11, 13, 17, 19, 23, 29, 31.

The product of 11 and any of the others will be less than 350, 6 products.

The product of 13 and any below 26 will be less than 350, 3 more products.

The product of 17 and any below 20 will be less than 350, 1 more product.

There are a total of 10 different products below 350 possible.

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11·13, 11·17, 11·19, 11·23, 11·29, 11·31, 13·17, 13·19, 13·23, 17·19

6 0
3 years ago
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