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vlabodo [156]
3 years ago
10

Please help I have a sucky teacher and don’t know what to do

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
4 0

Answer:

  1, 4, 3, 6, 2, 7, 5

Step-by-step explanation:

The circle operator in f\circ g means that the function named on the left (f) operates on the result of the function named on the right (g). So, the notation

  (f\circ g)(x)

means

  f(g(x))

That is, g(x) is computed and used as input to the function f. When the function definitions are as shown, the evaluation proceeds in these steps.

  (f\circ g)(-4)\\\\=f(g(-4))\quad\text{write as function of a function}\\\\=f(-2(-4)^2)\quad\text{put -4 for x in $g(x)$}\\\\=f(-2(16))\quad\text{evaluate $(-4)^2$}\\\\=f(-32)\quad\text{evaluate $g(-4)$}\\\\=2(-32-1)\quad\text{put -32 for x in $f(x)$}\\\\=2(-33)\quad\text{first step evaluating $f(-32)$}\\\\=-66\quad\text{value of $(f\circ g)(-4)$}

__

If your step choices at the bottom are numbered 1 to 7 left-to right, then the sequence is as shown in the Answer section above.

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Decide which of the two points on the graph of the line<br> X=0<br> A. 0,7<br> B. -4,0
MrMuchimi
When x = 0

A. 0, 7 is your answer

hope this helps
4 0
3 years ago
Is anyone able to figure this out, I can't do this
katrin [286]

Answer:

C. √2 - 1

Step-by-step explanation:

If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)

Let r = the radius of the small circle

Using Pythagoras' Theorem a^2+b^2=c^2

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

to find the diagonal of the square:

\implies r^2 + r^2 = c^2

\implies 2r^2 = c^2

\implies c=\sqrt{2r^2}

So the diagonal of the square = \sqrt{2r^2}

We are told that the radius of the large circle is 1:

⇒ Diagonal of square + r = 1

\implies \sqrt{2r^2}+r=1

\implies \sqrt{2r^2}=1-r

\implies 2r^2=(1-r)^2

\implies 2r^2=1-2r+r^2

\implies r^2+2r-1=0

Using the quadratic formula to calculate r:

\implies r=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\implies r=\dfrac{-2\pm\sqrt{2^2-4(1)(-1)}}{2(1)}

\implies r=\dfrac{-2\pm\sqrt{8}}{2}

\implies r=-1\pm\sqrt{2}

As distance is positive, r=-1+\sqrt{2}=\sqrt{2}-1  only

5 0
2 years ago
Read 2 more answers
Find an equation for the line with the given properties. Express the equation in slope-intercept form.
EleoNora [17]

Answer:

y = 3x - 19

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Define variables

Slope <em>m</em> = 3

Random point (5, -4)

Step 2: Plug in known variables

y = 3x + b

Step 3: Find <em>b</em>

-4 = 3(5) + b

-4 = 15 + b

b = -19

Step 4: Write linear equation

y = 3x - 19

8 0
3 years ago
If the price of rail season tickets increases by 4% every year, work out the price after 3
Zarrin [17]

Answer:

3048 x 1.04 ^3 = 3428.585474

4 0
3 years ago
For each day that Sasha travels to work, the probability that she will experience a delay due to traffic is 0.2. Each day can be
lions [1.4K]

Answer:

0.8213

Step-by-step explanation:

-This is a binomial probability problem given by the function:

P(X=x)={n\choose x}p^x(1-p)^{n-x}

Given that n=21 and p=0.2, the probability that she experience a delay on at least 3 days is calculated as:

P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 3)=1-P(X

Hence, the probability that she experience delay on at least 3 days is 0.8213

6 0
3 years ago
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