Number of red marbles in bag = r. b = 10-rProbability of first marble being red: r/10Second marble being red: (r-1)/9total probability = 2/15 = (r-1)*r/90r = 4b = 6
Step-by-step explanation:
"must be used first" is a very hard phrasing. multiplication is commutative.
and I am not sure that the problem is stated correctly.
I read here
(i×y²) to the power of 1/3.
i is the imaginary constant sqrt(-1) ?
exponents brought themselves to the power of something else multiply.
e.g.
![({2}^{3})^{4} = {2}^{12}](https://tex.z-dn.net/?f=%28%7B2%7D%5E%7B3%7D%29%5E%7B4%7D%20%20%3D%20%20%7B2%7D%5E%7B12%7D%20)
exponents in multimedia expressions of the same base simply add up.
e.g.
![{2}^{3} \times {2}^{4} = {2}^{7}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B3%7D%20%20%5Ctimes%20%20%7B2%7D%5E%7B4%7D%20%20%3D%20%20%7B2%7D%5E%7B7%7D%20)
a negative exponent means that the expression with the same positive exponent is just at the bottom of a division.
e.g.
![{2}^{ - 3} = 1 \div {2}^{3}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B%20-%203%7D%20%20%3D%201%20%5Cdiv%20%20%7B2%7D%5E%7B3%7D%20)
and a fraction as exponent specifies a root to be taken.
e.g
![{2}^{1 \div 3} = \sqrt[3]{2}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B1%20%5Cdiv%203%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B2%7D%20)
so, I would do all the exponent multiplications to simplify the expression.
![\sqrt[3]{i \times {y}^{2} } = ({i \times {y}^{2} })^{1 \div 3} =](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bi%20%5Ctimes%20%20%7By%7D%5E%7B2%7D%20%7D%20%20%3D%20%20%28%7Bi%20%5Ctimes%20%20%7By%7D%5E%7B2%7D%20%7D%29%5E%7B1%20%5Cdiv%203%7D%20%20%3D%20)
![= ( { - 1}^{1 \div 2} \times {y}^{2} ) ^{1 \div 3}](https://tex.z-dn.net/?f=%20%3D%20%28%20%7B%20-%201%7D%5E%7B1%20%5Cdiv%202%7D%20%20%5Ctimes%20%20%7By%7D%5E%7B2%7D%20%29%20%5E%7B1%20%5Cdiv%203%7D%20)
1/2 × 1/3 = 1/6
2 × 1/3 = 2/3
![= { - 1}^{1 \div 6} \times {y}^{2 \div 3} = \sqrt[6]{ - 1} \times \sqrt[3]{ {y}^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%7B%20-%201%7D%5E%7B1%20%5Cdiv%206%7D%20%20%5Ctimes%20%20%7By%7D%5E%7B2%20%5Cdiv%203%7D%20%20%3D%20%20%5Csqrt%5B6%5D%7B%20-%201%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B%20%7By%7D%5E%7B2%7D%20%7D%20)
so, as we can see, we can move freely from multiplying the fraction exponents to converting them into root expressions and vice versa.
Answer: The answer is -x^2 + 12x + 5
Answer:
Step-by-step explanation:
y = 5x + 4
-5x + y = 4 ----------------------(i)
3x + 2y = 20 --------------------(ii)
Multiply equation (i) by (-2)
(i)* (-2) 10x - 2y = -8
(ii) <u>3x + 2y = 20</u> { Now add this two equations}
13x = 12 { -2y and 2y got eliminated}
x = 12/13
Plug in value of x in (i)
-5*12/13 + y = 4
-60/13 + y = 4
y = 4 + 60/13
![y=\frac{4*13}{1*13}+\frac{60}{13}\\\\=\frac{52}{13}+\frac{60}{13}\\\\=\frac{112}{13}\\\\=8\frac{8}{13}y=](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B4%2A13%7D%7B1%2A13%7D%2B%5Cfrac%7B60%7D%7B13%7D%5C%5C%5C%5C%3D%5Cfrac%7B52%7D%7B13%7D%2B%5Cfrac%7B60%7D%7B13%7D%5C%5C%5C%5C%3D%5Cfrac%7B112%7D%7B13%7D%5C%5C%5C%5C%3D8%5Cfrac%7B8%7D%7B13%7Dy%3D)