If H is the circumcenter, then each of EH, FH, and GH are perpendicular bisectors of the legs BC, CD, and DB, respectively. So, for instance, EH cuts BC in half so that BE and EC have the same length.
Also, BH, CH, and DH are radii to the circumcircle of the triangle, so they all have the same length.
(1) CD = CF + FD = 2 • FD = 2 • 32 = 64
(2) CE = BE = 26
(3) HD = HC = 33
(4) GD = 1/2 • BD = 1/2 • 58 = 29
(5) By the Pythagorean theorem,
HG² + GD² = HD²
so
HG = √(33² - 29²) = 2 √(62)
(6) Similar to (5); by the Pythagorean theorem,
HF² + FD² = HD²
so
HF = √(33² - 32²) = √(65)
Based on the given coordinates of the quadrilateral ABCD, the slopes of the lines given at:
- Slope of AB = -7/4
- Slope of BC = 1/7
- Slope of CD = -5/3
- Slope of AD = 1/2
<h3>What are the slopes of the line?</h3>
The slope of AB is:
= (3 - (-4)) / (-4 - 0)
= -7/4
The slope of BC:
= (4 - 3) / (3 - (-4))
= 1/7
The slope of CD:
= (-1 - 4) / (6 - 3)
= -5/3
The slope of AD:
= (-1 - (-4)) / (6 - 0)
= 1/2
The rest of the question is:
The slope of AB ¯ ¯ ¯ ¯ ¯ is , the slope of BC ¯ ¯ ¯ ¯ ¯ is , the slope of CD ¯ ¯ ¯ ¯ ¯ is , and the slope of AD ¯ ¯ ¯ ¯ ¯.
Find out more on the slope of line at brainly.com/question/3493733.
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Answer:
10,000
Step-by-step explanation:
The base for a normal log is 10. You raise the base by the answer, which is 4. 
is 10,000.
