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hammer [34]
3 years ago
5

Pls help me!!!! I'm stuck on how to solve this!!??

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
4 0
Let A represent the value of the car after each year.
A= initial value (P)×(1+percent increase(r)) ^time
A=P×(1+r)^t
A=18710×(1+(-12%))^8
A=18710×(1-12%)^8
A=18710×(1-0.12)^8
A=18710×(0.88)^8
A= 6728.7619591115
The best approximation is 6729
Therefore the value of the car will be about $6729 after 8 years
Your answer is B.
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Maisie bought a house.
sergeinik [125]

Answer:

55.52+10=65.52%

65.52 divide 3=21.84%

Ans:21.84%

7 0
3 years ago
90 hazelnuts have a mass of 125 g. Hazelnuts have 630 calories per 100 g. work out the number of calories per hazelnut
jenyasd209 [6]

90 hazelnuts = 125g

Therefore, the mass of one hazelnut is this...

90 / 90 = 125 / 90

1 hazelnut = 25/18 grams


630 calories = 100 grams

100 divided by 25/18 = 72

Therefore...

630 / 72 = 1 hazelnut

AND THE ANSWER IS

8.75 calories = 1 hazelnut

8 0
3 years ago
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Dawn draws 1 card, replaces it, and draws another card. Is it more likely that she draws 2 red cards or 2 face cards?
Art [367]
Two red cards pls trust
5 0
3 years ago
Please answer this question please ​
Bas_tet [7]
<h3>Answer:</h3><h3 /><h3>Amount = Rs 13891.50</h3><h3>Compound interest = Rs 1891.50</h3>

Step-by-step explanation:

C = Amount (A) - Principal (P)

Where

C is the compound interest

To find the amount we use the formula

A = P ({1 +  \frac{r}{100} })^{n}

where

P is the principal

r is the rate

n is the period / time

From the question

P = Rs 12, 000

r = 5%

n = 3 years

Substitute the values into the above formula

That's

A = 12000 ({1 +  \frac{5}{100} })^{3}  \\ A = 12000(1 + 0.05)^{3}  \\ A = 12000 ({1.05})^{3}

We have the answer as

<h3>Amount = Rs 13891.50</h3>

Compound interest = 13891.50 - 12000

<h3>Compound interest = Rs 1891.50</h3>

Hope this helps you

8 0
3 years ago
Solve the following system of equations. 2x + y = 3 x = 2y - 1 Make sure there are NO SPACES in your answer. Include a comma in
mrs_skeptik [129]

Answer:  x=1;y=1 or (1,1)

Step-by-step explanation:

You can apply the Method of substitution.

Knowing that  x = 2y - 1 (second equation), you can substitute it into the first equation and solve for the variable y:

2x+y=3\\2(2y - 1)+y=3\\4y-2+y=3\\5y=3+2\\5y=5\\y=1

Now you need to substitute y=1 into the second equation x = 2y - 1 to calculate the value of the variable x. Then:

x = 2(1) - 1\\x=2-1\\x=1

Then, the solution is:

x=1;y=1 or (1,1)

5 0
3 years ago
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