Explanation:
Knowing the pH, you know the concentration of protons:
−log[H+]=pH=3.7
[H+]=10−3.7 M
Now, since the weak (monoprotic) acid dissociates into its conjugate base and a proton, the mols of protons are equimolar with the mols of conjugate base---the protons came FROM the weak acid, so the conjugate base that forms must be equimolar with the protons given out to the solvent.
HA⇌A−+H+
Hence, [A−]=[H+] in the same solution volume. Using the equilibrium constant expression, we get:
Ka=[H+]2eq[HA]eq
Don't forget that the HA form of HA had given away protons, so the mols of protons given away to generate A− is subtracted from the mols of (protons in) HA.
=[H+]2eq[HA]i−[H+]eq
=(10−3.7M)20.02M−10−3.7M
Ka=2.0105×10−6 M
Answer:
11.958129200057586 molecules
Explanation:
___3% H2O2 (mass/vol)
<span>a) mass bought = 3g/100ml * 250 ml = ?? g H2O2 </span>
<span>b) moles / 0.250 liter = (?? g H2O2 / MW H2O2 g/mole) / 0.250 liter = ??M </span>
<span>Plug and SOLVE </span>
<span>Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem.
</span>
A variable is any factor,trait, or condition that can exist in differing amounts or types.
Answer:
b. po
Explanation:
that I was going to be a salted water and the kids and a half hours to go to misdeed I have to go back and I don't know if you don't want you so bad that you have to go back and I don't know if you don't have any money on me to get a new for me and I don't think so too baby and you are so sweet to see the new