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Brut [27]
1 year ago
12

Which layer of the atmosphere is between the mesosphere and the exosphere?

Chemistry
1 answer:
Genrish500 [490]1 year ago
6 0
C. Thermosphere is the correct answer
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Typhoons are large storms that form over the Pacific Ocean Hurricanes are large storms that form over the Atlantic Ocean. Which
Liula [17]
D. Drop in barometric pressure, warm ocean water, humid air. The low pressure brings in a cool air mass causing collision of two different masses.

My father rode out a typhoon near Okinawa WWII, onboard the battleship USS Missouri BB-63.

Violent pitching, alarms going off for approaching capsize pitch. The captain came on loudspeaker “ don’t worry men, land is near... about a mile straight down”.
8 0
2 years ago
PLEASE HELP!!!<br><br> What is the mass of one lead atom in amu?
alexandr402 [8]

Answer: 207.2

Explanation:

In imprecise terms, one AMU is the average of the proton rest mass and the neutron rest mass. This is approximately 1.67377 x 10 -27 kilogram (kg), or 1.67377 x 10 -24 gram (g). The mass of an atom in AMU is roughly equal to the sum of the number of protons and neutrons in the nucleus.

7 0
2 years ago
Read 2 more answers
Dihydrogen monoxide is a(n) ____. A. covalent compound B. molecular formula C. empirical formula D. Ionic compound​
olga_2 [115]

Answer:

D. Ionic compound

Explanation:

Just based on my opinion

Correct me if I'm wrong tnx:<

8 0
2 years ago
What coefficient for O2 demonstrates the law of conservation of mass?
olga2289 [7]

Answer:

2

Explanation:

The coefficient for O is 2 and this is an example of a combustion reaction. With the help of the coefficient 2 infront of oxygen, this equation now demonstrates law of conservation of mass.

6 0
3 years ago
NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.084 M in
kolbaska11 [484]
Answer is: pH of solution is 5,17.
Kb(NH₃) = 1,8·10⁻⁵.
c(NH₄Cl) = 0,084 M = 0,084 mol/L.
Chemical reaction: NH₄⁺ + H₂O → NH₃ + H₃O⁺.
Ka · Kb = 10⁻¹⁴.
Ka(NH₄⁺) = 10⁻¹⁴ ÷ 1,8·10⁻⁵.
Ka(NH₄⁺) = 5,55·10⁻¹⁰.
[H₃O⁺] = [NH₃]  = x.
Ka(NH₄⁺) = [H₃O⁺] · [NH₃] ÷ [NH₄⁺].
5,55·10⁻¹⁰ = x² ÷ (0,084 M - x).
Solve quadratic equation: x = [H₃O⁺] = 6,8·10⁻⁶ M.
pH = -log[H₃O⁺].
pH = -log(6,8·10⁻⁶ M) = 5,17.
7 0
3 years ago
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