Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
Answer:
See explaination
Explanation:
class Taxicab():
def __init__(self, x, y):
self.x_coordinate = x
self.y_coordinate = y
self.odometer = 0
def get_x_coord(self):
return self.x_coordinate
def get_y_coord(self):
return self.y_coordinate
def get_odometer(self):
return self.odometer
def move_x(self, distance):
self.x_coordinate += distance
# add the absolute distance to odometer
self.odometer += abs(distance)
def move_y(self, distance):
self.y_coordinate += distance
# add the absolute distance to odometer
self.odometer += abs(distance)
cab = Taxicab(5,-8)
cab.move_x(3)
cab.move_y(-4)
cab.move_x(-1)
print(cab.odometer) # will print 8 3+4+1 = 8
