All categories

2 years ago

The type of torque wrench designed for tightening clamping bands on underground pipe is the ___________________

Physics

2 answers:

lana [24]2 years ago

6 0

The type of torque wrench designed for tightening clamping bands on underground pipe is the <u>no-hub type</u>

<u></u>

A no-hub type torque wrench is a tool that is generally used for plumbing and pipe installation work.

<h3>What is plumbing? </h3>

Plumbing is the set of activities in which modifications, installations, replacements, maintenance or repairs of pipes and accessories related to water drainage are carried out.

Learn more about plumbing at: brainly.com/question/890547

#SPJ4

Juli2301 [7.4K]2 years ago

3 0

The type of torque wrench designed for tightening clamping bands on underground pipe is the …No-Hub..

You might be interested in

If you wanted to move an electron from the positive to the negative terminal of the battery, how much work W would you need to d

brilliants [131]

a lot of electric so that the battery can work

8 0

4 years ago

Which wave shows the loudest sound below?

pochemuha

Answer:

I think C

Explanation:

If im right give brainliest :)

8 0

3 years ago

Read 2 more answers

A wave's frequency is 2 Hz and its wavelength is 4 m. What is the wave's speed?

juin [17]

Answer:

Speed is distance over time, so v = λ / T. The frequency, f, is 1/T, so the equation relating wave speed, frequency, and wavelength is v = f λ .

Explanation:

please mark me as brainliest thank you

3 0

3 years ago

Explain why meteorologists compare new weather maps and weather maps that are 24 hours old

lawyer [7]

To see which way atmospheric conditions and meteorological phenomena are moving, and how fast.

Also to see whether they were correct yesterday.

3 0

4 years ago

AEROSPACE On the Moon, a falling object falls just 2.65 feet in the first second after being dropped. Each second it falls 5.3 f

aniked [119]

Answer:

d = 265 ft

Therefore, an object fall 265 ft in the first ten seconds after being dropped

Explanation:

This scenario can be represented by an arithmetic progression AP.

nth term = a + nd

Where a is the first term given as 2.63 ft.

d is the common difference and is given as 5.3ft.

n is the particular second/time.

To calculate how far the object would fall in the first 10 seconds, we can derive it using the sum of an AP.

d = nth sum = (n/2)(2a+(n-1)d)

Where n = 10 seconds

a = 2.65 ft

d = 5.3 ft

Substituting the values we have;

d = (10/2)(2×2.65 + (10-1)5.3)

d = 265 ft

Therefore, an object fall 265 ft in the first ten seconds after being dropped

4 0

3 years ago

Read 2 more answers